All categories

3 years ago

How could I tell if an egg is hard boiled or raw explain using Newton's law of motion

Physics

1 answer:

Thepotemich [5.8K]3 years ago

6 0

Answer:

Explanation:

Newton's 2 nd law of motion tells that when equal torque is applied on object having higher moment of inertia , it will rotate slower .

Moment of inertia of boiled egg is higher because the whole egg rotates as s solid unit . Hence it will rotate slower or it rolls slower on an inclined surface .

In this way by applying Newton's law , we can identify raw or boiled egg .

You might be interested in

A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?

bezimeni [28]

Answer:

$45 J$

Explanation:

The equation for work is:

$Work=Force*Distance$

We can substitute the given values into the equation:

$Work=15N*3m\\Work=45Nm\\Work=45J$

7 0

2 years ago

Read 2 more answers

A 16 foot ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 3 feet per second, how fa

JulsSmile [24]

Answer:

11.625

Explanation:

L = length of the ladder = 16 ft

$v_{y}$ = rate at which top of ladder slides down = - 3 ft/s

$v_{x}$ = rate at which bottom of ladder slides

y = distance of the top of ladder from the ground

x = distance of bottom of ladder from wall = 4 ft

Using Pythagorean theorem

L² = x² + y²

16² = 4² + y²

y = 15.5 ft

Also using Pythagorean theorem

L² = x² + y²

Taking derivative both side relative to "t"

$0 = 2x\frac{\mathrm{d} x}{\mathrm{d} t} + 2y\frac{\mathrm{d} y}{\mathrm{d} t}$

$0 = x v_{x} + y v_{y}$

$0 = 4 v_{x} + (15.5) (- 3)$

$v_{x}$ = 11.625 ft/s

7 0

3 years ago

What is the momentum of a 200 kg truck travelling at 20 m/s?

geniusboy [140]

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

$p=200\times 20\\\\p=4000\ kg-m/s$

So, the momentum of the truck is equal to 4000 kg-m/s.

8 0

3 years ago

A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un

KonstantinChe [14]

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

$x=vt=23.3\frac{m}{s}t$

and the police car distance:

$x=vt+\frac{at^{2}}{2}=0+\frac{2.75\frac{m}{s^{2}} t^{2}}{2}=0.73\frac{m}{s^{2}}$

Since they both travel the same distance x, we can equal both formulas and solve for t:

$0 = 0.73\frac{m}{s^{2}}t^{2}-23.3\frac{m}{s} t\\\\0=t(0.73\frac{m}{s^{2}}t-23.3\frac{m}{s} )\\\\$

Two solutions exist to the equation; the first one being $t=0$

The second solution will be:

$0.73\frac{m}{s^{2}}t=23.3\frac{m}{s}\\\\t=\frac{23.3\frac{m}{s}}{0.73\frac{m}{s^{2}}}=32s$

This result allows us to confirm that the police car will take 32s to catch up to the speeder

7 0

3 years ago

If the man on the left pulls on the object with a force of 500 N and the man on the right pulls on the object with a force of 75

Igoryamba

Force is a vector quantity
so pulling from opposite side will be negative
so
750+(-500)= 250N
C is the right answer
becauseause the man on the right applies greater force.

3 0

3 years ago