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Nostrana [21]
3 years ago
11

What kind of motion for a star does not produce a Doppler effect? Explain.

Physics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

 Transverse motion does not produced a doppler effect for a star. As, the doppler effect are occurred when the object are emitting light either in the direction towards the observer or moving away. The various astronomical objects are moving and the observer observed the blue wavelength of the light.

Doppler effect in the star is the process when the observer moves towards the star then it seems like the star move towards the observer.

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A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

f = f_{0}\frac{v + v_{o}}{v - v_{s}}        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

v_{o}: is the speed of the observer = 0 (it is heard in the town)

v_{s}: is the speed of the source =?

The frequency of the train before slowing down is given by:

f_{b} = f_{0}\frac{v}{v - v_{s_{b}}}  (1)                  

Now, the frequency of the train after slowing down is:

f_{a} = f_{0}\frac{v}{v - v_{s_{a}}}   (2)  

Dividing equation (1) by (2) we have:

\frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}}

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}}   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

v_{s_{b}} = 2v_{s_{a}}     (4)

Now, by entering equation (4) into (3) we have:

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}}  

\frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}}

By solving the above equation for v_{s_{a}} we can find the speed of the train after slowing down:

v_{s_{a}} = 11.06 m/s

Finally, the speed of the train before slowing down is:

v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

7 0
3 years ago
Explain with one example that different types of organisums live in one habitation​
inn [45]

Answer:

When you look at a simple koi pond you can find Koi (the secondary consumer) that feeds off of the zooplankton (first consumer), they eat the phytoplankton (producers). All in a simple food chain

Explanation:

Basically, Koi eat the little animal plankton (zooplankton) that then eats the plant plankton (phytoplankton) that can only end when a part of that habitat is removed. If you got rid of the plant plankton then the whole chain would collapse and most likely die.

5 0
3 years ago
How do waves interact with our senses?
k0ka [10]

Answer:

well sound waves interact with our ears and light interacts with our vision

Explanation:

5 0
3 years ago
Read 2 more answers
How are weather satellites and weather stations similar?
alexandr402 [8]
<span>Weather satellites and weather stations are similar, because they both have the same purpose. They are used to help predict future weather as well as as current conditions. The satellites are viewing the weather from a distance at a large scope, but stations are using data they collect on earth to help with the same task.</span>
6 0
4 years ago
Pressure increases with depth towards the center of earth. In which layer would you expect pressure to be the greatest.
Amiraneli [1.4K]
You could expect to find it in the inner core
8 0
3 years ago
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