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2 years ago

Can someone please help I’m not so good at fractions

Mathematics

2 answers:

satela [25.4K]2 years ago

7 0

Answer:

A) 25/33

B) 36

C) 1/15

d) 2 11/12

E) 1 7/12

USPshnik [31]2 years ago

7 0

25/33
36
1/15
2 11/12
17/12

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What is the absolute value of a number ?

stepladder [879]

Answer:

Step-by-step explanation:

The absolute value (or modulus) | x | of a real number x is the non-negative value of x without regard to its sign. For example, the absolute value of 5 is 5, and the absolute value of −5 is also 5. The absolute value of a number may be thought of as its distance from zero along real number line.

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME! CLICK ON THE PICTURE FOR A BETTER VIEW IF U NEED TO!

masya89 [10]

Answer:

In order: -5, 3, 5

Step-by-step explanation:

-5g + 15h - 25

-5 ( g - 3h + 5 )

Hopefully this helps!

Brainliest please?

3 0

2 years ago

Simplfy (x)^2(2xy^3)^5 plz help

Deffense [45]

Answer: 32x^7y^15

Step-by-step explanation:

(x)^2(2xy^3)^5

= x^2 * 32x^5y^15

= 32x^7y^15

5 0

2 years ago

The power a windmill can generate is a function of the velocity of the wind. The function can be approximated by P = f(v) = 0.01

aleksandr82 [10.1K]

Answer:

25.920 W

Step-by-step explanation:

Fill in the given number and do the arithmetic.

P = f(12) = 0.015(12^3) = 25.920 . . . . . watts

8 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago