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mezya [45]
3 years ago
9

Instructions: Find the missing side. Round your answer to the nearest

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

x = 16.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 66 = 15/x

x sin 66 = 15

x = 15/sin 66

x=16.41954

Rounding to the nearest tenth

x = 16.4

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Just answer the question in simple words lol
rusak2 [61]

Answer:

He should have multiplied 15 tsp by 1 tbsp/3tsp.

Step-by-step explanation:

The tsp labels cancel each other out when one is the numerator and one is the denominator.

15tsp x 1 tbsp/3tsp = 15/3 = 5 tbsp

7 0
3 years ago
Read 2 more answers
Writing Equations
LekaFEV [45]

Answer:

The Variables are X & Y

The Coefficients are 1/4 & 3

and the Constants are -23 and 42

Step-by-step explanation:

it's correct on edge!

8 0
3 years ago
The equation for (30x+4) is
antoniya [11.8K]

Answer:

2(15x + 2)

6 0
3 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
Crazy boy [7]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

8 0
3 years ago
14-3(5t-12)=1-(20t+1)<br> How am I supposed to do this?
Nuetrik [128]
Expand by multiplying out:

14-15t + 36 = 1 -20t -1,
Because of the minus before the bracket, it changes the sign inside the bracket
-15t + 20t  = 1-1-14-36  Rearranging the ts on one side and the numbers on other
                                   side.
5t = -50  Divide both sides by 5.
t =  -50/5
t = -10.


5 0
4 years ago
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