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Archy [21]
4 years ago
5

Can someone please answer this question please answer it correctly and please show work please help I need it

Mathematics
1 answer:
scZoUnD [109]4 years ago
7 0

Answer:

A

Step-by-step explanation:

a =  - x \\ - ( - x) - 1 =  + x - 1.....x > 1 =  > x - 1 \: is \: positive.

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An artist combines copper and other metals to make bronze. A bronze sculpture
natka813 [3]

Answer:

The dolphin statue is 86% copper, while the bird statue is 83% copper, making the dolphin sculpture more coppery.

Step-by-step explanation:

Since an artist combines copper and other metals to make bronze, and a bronze sculpture of a dolphin contains 43 g of copper for every 7 g of other metals, while a bronze sculpture of a bird contains 83 g of copper for every 17 g of other metals, to determine which sculpture is more coppery the following calculation must be performed:

Dolphin:

43 + 7 = 50

50 = 100

43 = X

43 x 100/50 = X

86 = X

Bird:

83 + 17 = 100

100 = 100

83 = X

83 x 100/100 = X

83 = X

Therefore, the dolphin statue is 86% copper, while the bird statue is 83% copper, making the dolphin sculpture more coppery.

3 0
3 years ago
In the given figure AOB is a straight line find the value of x.<br>Please tell the correct answer..​
Scilla [17]

Answer:

2x+5x+3x=180°

10x=180°

x=180/10

x=18° ans..

5 0
3 years ago
Read 2 more answers
[50 Points]
Snezhnost [94]
60 days / 8 workers = 7.5

60 days - 12 days of work done = 48

48 x 7.5 = 360

360/ 12 workers = 30 days to finish rest of the house.
8 0
3 years ago
Read 2 more answers
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
Which of the following is a perfect square?
o-na [289]
Greeting's!

<span>B. 279
_____
</span>
3 0
3 years ago
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