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trasher [3.6K]
2 years ago
7

PLEASE HELP

Mathematics
1 answer:
Anna007 [38]2 years ago
4 0
I don’t really know let me ask my friends 1
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1. f(x) = x^3– 4x^2 – 7x + 10
True [87]

9514 1404 393

Answer:

  zeros: {-2, 1, 5}

Step-by-step explanation:

A graphing calculator works nicely for identifying turning points, roots, increasing/decreasing intervals, and more.

8 0
3 years ago
Solve for x: [x - 2 + 10 = 12
Monica [59]

Answer:x-2+10=12

We move all terms to the left:

x-2+10-(12)=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

Step-by-step explanation:

5 0
3 years ago
Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
In the problem 4x + 10 list a term, factor, coefficient, and constant.​
kifflom [539]

term- 4x and 10

This is because to be a term it has to be + or -

Factor- 4x+10

This is because that is what is happening in the problem

Coefficient- 4y

I don't know what the constant would be, But I hope that this helps you

6 0
3 years ago
What is the cheapest way to buy 48 cans of cola
Inga [223]

Answer:

both the first one

Step-by-step explanation:

use unit rate

4 0
3 years ago
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