Hi there!
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I believe your answer is:
Option C
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Here’s why:
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Hope this helps you. I apologize if it’s incorrect.
Answer:
Step-by-step explanation:
N(106,14²)
(calculated using excel, let me know if you were supposed to use a normal table) = 0.4715
85.34
Q1:96.56
Q3:115.44
IQR (which is Q3-Q1)= 115.44-96.56= 18.88
Answer:
it would be 4.5
Step-by-step explanation:
basic explantion
step 1. 3+2 =5
step 2 5x5=25
step 3 25-16=9
step 4 9 divde by 2= 4.5
simplifyed it would be 25-16 ÷ 2
more deatialed explanation.
I added 3+2 to get 5 and i sqaured the 5 to get 25 becasue 5x5 is 25 then i took away 16 and got 9 then i divde 9 by 2 to get 4.5. hope this helped!
Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
