PLEASE HELP

Mathematics

1 answer:

Anna007 [38]3 years ago

4 0

I don’t really know let me ask my friends 1

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X/-2=4, X/3+13=13, Z/2+2=4 plz show ur work and explain how u did it

AVprozaik [17]

$\dfrac{x}{-2}=4\ \ \ |multiply\ both\ sides\ by\ (-2)\\\\(-2)\cdot\dfrac{x}{-2}=(-2)\cdot4\\\\\boxed{x=-8}\\\\\dfrac{x}{3}+13=13\ \ \ |subtract\ 13\ from\ both\ sides\\\\\dfrac{x}{3}+13-13=13-13\\\\\dfrac{x}{3}=0\ \ \ |multpily\ both\ sides\ by\ 3\\\\\not3^1\cdot\dfrac{x}{\not3_1}=0\\\\\boxed{x=0}$

$\dfrac{z}{2}+2=4\ \ \ |subtract\ 2\ from\ both\ sides\\\\\dfrac{z}{2}+2-2=4-2\\\\\dfrac{z}{2}=2\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{z}{\not2_1}=2\cdot2\\\\\boxed{z=4}$

6 0

3 years ago

What number needs to be added to both sides of the equation to complete the square? X^2−7x=5 Enter your answers in the boxes.

Andrew [12]

ANSWER

We need to add half the coefficient of $x$ all square.