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2 years ago

PLEASE HELP

Mathematics

1 answer:

Anna007 [38]2 years ago

4 0

I don’t really know let me ask my friends 1

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I NEED HELP :( WILL MARK BRAINLIEST!! NEED HELP ASAP

Elden [556K]

Answer:

the answer is B

Step-by-step explanation:

The lowest point for Y is -1 therefore that's the first number and the highest point is 1 therefore thats the last number so naturally the range is -1≤Y≤1

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3 years ago

Can you please help me with this

Brrunno [24]

Just do 2000-586.40 and that will get you the remaining money they need to raise!:)

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3 years ago

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There are twelve people on the jury there were 4more man than women how many man were <br>there/

irina1246 [14]

$x-the \ number \ of \ women \\ x+4 -the \ number \ of \ men \\\\ x+x+4=12 \\\\ 2x+4=12 \\\\ 2x=12-4 \\\\ 2x=8 \\\\ \boxed{x=\frac{8}{2}=4 \ women} \\\\ x+4= \\\\ = 4+4\to\boxed{8 \ men}$

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3 years ago

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How do you say 1.75 in words

gizmo_the_mogwai [7]

You would say one and seventy-five hundredths

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3 years ago

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Y = 3(x-2)^2 + 5

Orlov [11]

The y-intercept coordinate is at the point (0, 17)

<h3>Properties of functions</h3>

Given the following function expressed as:

$y = 3(x-2)^2 + 5$

The vertex of the function (h, k) is (2, 5) while the axis of symmetry is at x = 2
Domain are the input values for which the function exist. According to the function, the domain and range exists on all real values

The x-intercept is the point where y = 0

$3(x-2)^2 + 5=0\\3(x-2)^2 = -5\\(x-2)^2 = -5/3\\x - 2 = 25/9\\x = 25/9 + 2\\x = \frac{43}{9}$

Hence the x-intercept is (43/9, 0)

The y-intercept is the point where x = 0

$y=3(x-2)^2 + 5\\y=3(-2)^2 + 5\\y=12+5\\y=17$

The y-intercept coordinate is at the point (0, 17)

Learn more on vertex and axis of symmetry here: brainly.com/question/21191648

3 0

2 years ago