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3 years ago

12

How many area codes (ABC) would be possible if the first 2 digits can be any number 1-9 & last digit can be any number 4-7?

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1 answer:

erik [133]3 years ago

4 0

1st digit can be 1-9 which is 9 numbers

2nd digit can be 1-9 which is 9 numbers

3rd digit can be 4-7 which is 4 numbers.

Total combinations = 9 x 9 x 4 = 324

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