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Setler79 [48]
2 years ago
12

How many area codes (ABC) would be possible if the first 2 digits can be any number 1-9 & last digit can be any number 4-7?

just type in the answer​
Mathematics
1 answer:
erik [133]2 years ago
4 0

1st digit can be 1-9 which is 9 numbers

2nd digit can be 1-9 which is 9 numbers

3rd digit can be 4-7 which is 4 numbers.

Total combinations = 9 x 9 x 4 = 324

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We must get x onto it's own side, so subtract y from both side.s

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Simplify.

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