How many area codes (ABC) would be possible if the first 2 digits can be any number 1-9 & last digit can be any number 4-7?
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1 answer:
1st digit can be 1-9 which is 9 numbers
2nd digit can be 1-9 which is 9 numbers
3rd digit can be 4-7 which is 4 numbers.
Total combinations = 9 x 9 x 4 = 324
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