Given:
The explicit formula of a sequence is
To find:
The third, fifth, and seventeenth terms of the sequence.
Solution:
We have,
For n=3,
For n=5,
For n=7,
Therefore, the third, fifth, and seventeenth terms of the sequence are -14.2, -19.2 and -24.2 respectively.
Answer:
nbr2 = 0
Step-by-step explanation:
Given
The following program segment
<em>nbr2 = 0 </em>
<em>calc = 1 </em>
<em>x= 7 </em>
<em>while x >=3: </em>
<em> calc = calc * x </em>
<em> x = x - 2</em>
<em />
Required
The value of nbr2
In the first line, nbr2 was initialized to 0 i.e.
<em>nbr2 = 0</em>
From the second line of the program till the last, no operation was carried out on nbr2
This means that nbr2 will maintain its original value (which is 0)
Hence,
<em>The value of nbr2 is 0</em>
The given equation is an equation of a circle because it looks similar to the general equation of a circle.
The general equation of a circle is:
x² + y² +2gx + 2fy + c = 0...........eq1
Where (-g, -f) is the center of the circle.
c is a constant
Given equation is
3x² +6x + 3y²+7y+4 = 0
Let us take 3 as common
x² + 2x+y²+7/3y + 4/3 = 0
Let us rearrange the equation
x² + y²+2x +7/3y + 4/3 = 0...........eq2
Now look at eq1 and eq2
We got that eq2 is having a similar pattern as eq1.
Therefore, The given equation is an equation of a circle.
To get more about circle visit:
brainly.com/question/1506955
x=1/2
10-2x=14x+2
8/16=16x/16
{(1,0)(,1,1),(1,2),(2,0),(2,1),(2,2),(3,0),(3,1),(3,2)}
Solution
A= {1,2,3}
B={0,1,2}
A×B ={(1,0),(1,1),(1,2),(2,0),(2,1),(2,2),(3,0),(3,1),(3,2)}