<span>1. Make y the subject
a) 4y=12x+18
y = 3x + 4.5
b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3
2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)
slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1
equation
y = 2.5x + 1
b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)
</span>y= 1/2X + 7
slope = 1/2
slope of line perpendicular = -2
passing through point (3,9)
y = mx + b
9 = -2 (3) + b
b = 15
equation
y = -2x + 15
Answer:
the answer is B and C
Step-by-step explanation:
Answer:
-18
Step-by-step explanation:
you add 12 and six together and you get 18. Then you put a negative sign in front of it
2x + 5y = 34
x+2y = 14
Multiply the second equation by two to create like terms for one variable.
2(x+2y = 14)
2x + 4y = 28
2x + 5y = 34
2x + 4y = 28 -- Subtract.
y = 34.28 = 6
Solve for x
x + 2(6) = 14
x + 12 = 14
x = 2
Check:
2 + 2(6) = 14
2 + 12 = 14
14 = 14
Answer:
X = 2
Y = 6
Answer:Put this in y= mx +b form
we have the slope(4) as well as a set of points for x and y so we have everything we need to solve for b
1= 4(2) + b
1 =8+b B=-7
so equation is y = 4x -7
Step-by-step explanation: can i get brainley? :)
