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2 years ago

The equation, 3x2 6x 3y2 7y 4 = 0, represents a conic. The conic represented by the equation is a/an because.

1 answer:

Taya2010 [7]2 years ago

3 0

The given equation is an equation of a circle because it looks similar to the general equation of a circle.

<h3>What is the general equation of a circle?</h3>

The general equation of a circle is:

x² + y² +2gx + 2fy + c = 0...........eq1

Where (-g, -f) is the center of the circle.

c is a constant

Given equation is

3x² +6x + 3y²+7y+4 = 0

Let us take 3 as common

x² + 2x+y²+7/3y + 4/3 = 0

Let us rearrange the equation

x² + y²+2x +7/3y + 4/3 = 0...........eq2

Now look at eq1 and eq2

We got that eq2 is having a similar pattern as eq1.

Therefore, The given equation is an equation of a circle.

To get more about circle visit:

brainly.com/question/1506955

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A cooler has 6 Dr Peppers, 5 Diet Cokes, 9 Cokes, and 4 Sprites in it.

liq [111]

Answer:

Step-by-step explanation:

6/24 multiplied by 5/24

7 0

3 years ago

How many miles is 2/3

Hoochie [10]

1 mile = 1760 yards

=2/3*1760

2*586.66

=1173.33 yards

hope this helps

5 0

3 years ago

Alex needs 2.5 yards of fabric to make a costume for homecoming .how many inches of fabric does he need?

zzz [600]

2.5*36=90 inches

Alex need 90 inches of fabric to make a costume for homecoming.

6 0

3 years ago

The function f(x) = |x| is shifted to the left 3 units and down 2 units to make the function g(x) . Write the equation g(x) that

Mila [183]

Answer:

g(x) = |x+3|-2

Step-by-step explanation:

to move horizontally replace each x with (x ± c)

if you move it to the right, you need x - c

if you move it to the left , you need x + c

so , since we are moving 3 units to the left, we replace the x with x+3

g(x) = |x+3|-2

4 0

3 years ago

Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

-------------

So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

5 0

2 years ago

Read 2 more answers