The answer will be
155 times 5 = 775
Answer:
45 yards and 176 yards
Step-by-step explanation:
Perimeter of a rectangular playing field = 2(Length + width)
P = 2(L+W)..................... Equation 1
From the question,
Let the width of the rectangular playing field = x yards,
The the Length = 4x-4 yards.
Given: P = 442 yards.
Substitute these values into equation 1
442 = 2(4x-4+x)
442/2 = 5x-4
221 = 5x-4
5x = 221+4
5x = 225
x = 225/5
x = 45 yards.
Width = 45 yards.
Length = (45×4)-4 yards = 176 yards
Hence the dimensions of the playing field are, 45 yards and 176 yards
Representa una ecuacion de segundo grado. :v
Answer:
x ≈ - 5.83 , x ≈ - 0.17
Step-by-step explanation:
x² + 6x + 1 = 0 ( subtract 1 from both sides )
x² + 6x = - 1
Using the method of completing the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(3)x + 9 = - 1 + 9
(x + 3)² = 8 ( take square root of both sides )
x + 3 = ± 
( subtract 3 from both sides )
x = - 3 ±
Then
x = - 3 - ≈ - 5.83 ( to 2 dec. places )
x = - 3 + ≈ - 0.17 ( to 2 dec. places )
