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ValentinkaMS [17]
3 years ago
14

CAN SOMEONE PLEASE HELP ME WITH GEOMETRY!! PLEASEEEEE!! I DONT NEED AN ANSWER!! I JUST NEED SOMEONE TO PLEASE EXPLAIN TO ME HOW

TO DO THIS!!

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

I think you have to subtract the to known numbers get the measurements between them.

Step-by-step explanation:

For example, 22 - 11 = 11 so the line segment with the question mark would be 11

I think :)

sorry if I'm wrong

Good luck

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Find a unit vector in the direction of the vector left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 8 2nd Row 1st Col
MrRissso [65]

Answer:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

Step-by-step explanation:

We are required to find a unit vector in the direction of:

\left[\begin{array}{c}-8\\7\\2\end{array}\right]

Unit Vector, \hat{a}=\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}

The Modulus of \overrightarrow{a} =\sqrt{(-8)^2+7^2+(-2)^2}=\sqrt{117}

Therefore, the unit vector of the matrix is given as:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

5 0
3 years ago
1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Nookie1986 [14]

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?


Point Slope form y − y1 = m(x − x1)


Y1: -7 x1:1 slope :-2/3


Y-(-7)=-2/3(x-1)

Y+7=-2/3(x-1)


2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?


Y-(-6)=1/3(x-(-2))


Y+6=1/3(x+2)



3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)


SlopeM: =change in y/change in x

M= -1-5/-3-4

M= -6/-7

M=6/7


So now slope:6/7, point (4,5)

Y-y1=m(x-x1)

Equation in point slope

Y-5=6/7(x-4)



6 0
3 years ago
Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity
iris [78.8K]

Answer:

(a) 7.5 seconds

(b) The horizontal distance the package  travel during its descent is 1737.8 ft

Step-by-step explanation:

(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀

The initial height of the object s₀ = 900 feet

The initial vertical velocity of the object v₀_y = 0 m/s

The time it takes the package to strike the ground is found as follows;

0 = -16·t² + 0×t + 900

900 = 16·t²

t² = 900/16 = 62.25

t = √62.25 = 7.5 seconds

(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

158 miles/hour = 231.7126 ft/s

The horizontal distance the package  covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place

The horizontal distance the package  travel during its descent = 1737.8 ft.

4 0
3 years ago
How to get the radical answer simplified
SSSSS [86.1K]
For 61 you can change it to √25/√49. √25=5 and √49=7 so it would simplify to 5/7.
3 0
3 years ago
The box plot shows the number of home runs hit by 43 players during a baseball season which stament best describes the data
ozzi

The number of data values between the lower quartile and the median is less than the number of data values between the upper quartile and the median.

Hope this helps!

6 0
3 years ago
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