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Masteriza [31]
3 years ago
13

Identify the type of sequence shown in the table below and select the appropriate response. n f(n) 1 540 2 500 3 460 4 420 5 380

arithmetic sequence; common difference is −40 arithmetic sequence; common difference is 40 geometric sequence; common ratio is −40 geometric sequence; common ratio is 40
Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

arithmetic sequence; common difference is −40

Step-by-step explanation:

An arithmetic sequence is a sequence in which each term is found by adding a constant, called the common difference, to each previous term.

In this sequence, we go from 540 to 500 to 460, etc.  Each time we are subtracting 40.  This is the same as adding -40; this makes the sequence arithmetic.

Evgen [1.6K]3 years ago
4 0
The answer is the first one; it is an arithmetic sequence with a common difference of -40.
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pav-90 [236]

Answer:

12

Step-by-step explanation:

if you combine the triangles (1/2) you get 6 since they are 0.5 of a unit divide by two = 3 add to 9 =12

7 0
2 years ago
Henry bought 5/6 pound of roasted almonds for five dollars he wants to know the price per pound
Andrej [43]

Answer:

$6

Step-by-step explanation:

p=pound

5/6p= 500

p= 500(6/5)

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Hope this helps!!!

8 0
3 years ago
The manager of a local nightclub has recently surveyed a random sample of 280 customers of the club. She would now like to deter
Lunna [17]

Answer:

z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007

p_v = P(z>2.007) = 0.0224

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

Step-by-step explanation:

We have the following info given:

\bar X = 35.6 represent the sampel mean for the age of customers

\sigma = 5 represent the population standard deviation

n = 280 represent the sample size selected

We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 35

Alternative hypothesis \mu >35

The statistic for this case is given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing the data given we got:

z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007

We can calculate the p value since we are conducting a right tailed test like this:

p_v = P(z>2.007) = 0.0224

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

5 0
3 years ago
Find the slope of the line through the points (−3, 6) and (2, 6).
Elden [556K]

Answer:

There wouldn't be a slope. It would be 0/5

Step-by-step explanation:

\frac{6-6}{2+3}

6 - 6 = 0

2 + 3 = 5

0/5 isn't a slope.

7 0
4 years ago
Read 2 more answers
Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti
sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = \frac{2}{3}*\frac{2}{3}=\frac{4}{9}

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = 1-\frac{4}{9}=\frac{5}{9}

5 0
3 years ago
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