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shutvik [7]
3 years ago
6

Ells go through periods of growth and division. Cell division occurs during

Biology
1 answer:
Scilla [17]3 years ago
3 0
Mitosis is when the cell divides
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In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive plant having fasciated fruit an
Pani-rosa [81]

Answer:

Recombination frequency, P = 0.23.

If the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked.

  • 1% of recombinations = 1 map unit
  • 23% = 23 map units

The genes for stem color and fruit type seem to be in the same chromosome, linked and 23 MP apart.

Explanation:        

In the present example, the genes for stem color and fruit type seem to be linked.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.  

In this way, we might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with <u>lower frequencies in the progeny</u><u>.</u>    

The following distribution of offspring is observed:

  • normal fruit, purple stems 38.5%
  • fasciated fruit green stems 38.5%
  • normal fruit, green stems 11.5%
  • fasciated fruit, purple stems 11.5%

38.5% + 38.5% + 11.5% + 11.5% = 100%

N (total number of individuals in the progeny) = 100

  • number of individuals with normal fruit, purple stems 38.5
  • number of individuals with fasciated fruit green stems 38.5
  • number of individuals with normal fruit, green stems 11.5
  • number of individuals with fasciated fruit, purple stems 11.5

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU).

P = Recombinant number / Total of individuals.

P = 11.5 + 11.5 / 100

P = 0.23  

We need to know that 1% of recombinations = 1 map unit = 1cm. Also, the maximum recombination frequency is always 50%.  This means that if the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked. FR 23% = 23 UM.  

 

6 0
2 years ago
The thin muscle that separates the thoracic and abdominal cavities is the __________ .
Zanzabum
Answer: diaphragm

Explanation:
The diaphragm separates the thoracic cavity from the abdominal and pelvic cavity.

The diaphragm is a sheet of internal skeletal muscle located below the thoracic cavity that houses the heart and lungs. Below the diaphragm is the abdominal cavity.

The diaphragm plays an essential function for respiration. When the diaphragm contracts, the volume of the thoracic cavity increases so that air is drawn into the lungs.
8 0
3 years ago
The data below was collected in the field while studying the effect of pH on the growth of
never [62]

Answer: Answer is c 8 500

Explanation: Find the growth, in this case it would be 4-12. So you want to find the difference between them by subtracting the two values. 12-4=8

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Where is the nucleolus located in the cell? What molecule does the nucleolus produce and what is the function of this molecule?
ahrayia [7]
The <span>nucleolus is located inside the Nucleus. </span>
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Mass = 63g
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The volume is mass density is h,w,l
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