Explain how you could find the difference of 1 and 0.1978.

Elena surveyed her classmates to see how many like to make jewelry. When she asked 20 of her classmates, 50 percent said they li

nordsb [41]

10 students of Elena's classmates like to make jewellery.

<u>Step-by-step explanation:</u>

Let total no.of classmates who liked the jewellery = x

Here, in the given problem, given she asked her classmates '20'. So, it clearly shows that total number of students/classmates = 20. Also, in that, 50% said like to make jewellery. Now find 'x' as below,

$x = 50 \% \text { of } 20$

$x = \frac{50}{100} \times 20$

$x = 10$

Hence, the total number of classmates who liked to make Jewellery = 10

5 0

3 years ago

Simplify the imaginary number sqr -75

m_a_m_a [10]

Answer:

5i $\sqrt{3}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

and $\sqrt{-1}$ = i

Given

$\sqrt{-75}$

= $\sqrt{25(3)(-1)}$

= $\sqrt{25}$ × $\sqrt{3}$ × $\sqrt{-1}$

= 5 × $\sqrt{3}$ × i

= 5i $\sqrt{3}$

3 0

3 years ago

A football player caught the ball and made a gain of 8 yards on the first play. On the next play the team lost 12 yards. How man

Elza [17]

Draw a number line with 10 positives and 10 negatives. Count from 0 to 8. Now, from 8, count back 12 spots. From that spot, go back to 0, which is their original position. The number you counted there is your answer.

4 0

3 years ago

Read 2 more answers

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$