3 years ago

Explain how you could find the difference of 1 and 0.1978.

Mathematics

1 answer:

weqwewe [10]3 years ago

8 0

You would just subtract .1978 from 1

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Five cupcakes and two cookies cost $19.75. Two cupcakes and four cookies cost $ 17.50.

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Step-by-step explanation:

Let x and y represent the cost of a cupcake and cookie respectively.

Given that;

Five cupcakes and two cookies cost $19.75.

$5x+2y=19.75 ---------- 1$

Two cupcakes and four cookies cost $17.50.

$2x+4y=17.50 --------------2$

Let's solve the simultaneous equation by elimination;

Multiply equation 1 by 2;

$10x+4y=39.50-------3\\$

Subtract equation 2 from equation 3;

$10x-2x+4y-4y=39.50-8x=22$

$8x=22$

divide both sides by 8

$\frac{8x}{8} =\frac{22}{8} \\x=2.75$

Since we have the value of x, let substitute into equation 1 to get y;

$5x+2y=19.75\\5(2.75)+2y=19.75\\13.75+2y=19.75\\2y=19.75-13.75\\2y=6\\y=\frac{6}{2} \\y=3.00$

therefore , the cost of cupcakes and cookies are;

$cupcakes= 2.75\\cookies= 3.00$

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2 years ago

Explain how you could find the difference of 1 and 0.1978.​

Explain how you could find the difference of 1 and 0.1978.