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ankoles [38]
4 years ago
12

Match teachers comments to definitionsplease help guys ♡♡♡♡♡​

Mathematics
2 answers:
Rashid [163]4 years ago
3 0
Duru’s-1st teacher comment
Oliver’s-3rd teacher comment
Carlos’s-2nd teacher comment

I really hope you get me:)))
garik1379 [7]4 years ago
3 0

Answer:

Duru's definition : Stupendous! Well done.

Oliver's definiton:

You seem to be confusing a circle and a sphere

Carlos' definition : Your definition needs to be much more precise

hope this helps :)

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Answer:

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Step-by-step explanation:

Solving an equation for a variable or constant means that we have to isolate the value on one side of the equation or write the whole equation in terms of that variable or constant.

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Solving v = \frac{4}{3}\pi r^3 for r

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\frac{3}{4}v = \pi r^3

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Solving a_{ave} = \frac{v_2-v_1}{t_2-t_1} for v2

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(t_2-t_1)a_{ave} = \frac{v_2-v_1}{t_2-t_1}(t_2-t_1)\\(t_2-t_1)a_{ave} = v_2-v_1

Adding v1 on both sides

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Solving v = \frac{4}{3}\pi r^3 for r gives us: r=\sqrt[3]{\frac{3v}{4\pi}}

Solving a_{ave} = \frac{v_2-v_1}{t_2-t_1} for v2 gives us: v_2 = (t_2-t_1)a_{ave}+v_1

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