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amm1812
3 years ago
8

Which statement best describes weather?

Chemistry
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

Weather is describes as the term of the temperature, humidity, wind velocity, precipitation, and barometric pressure. It usually happens in the troposphere, or lower atmosphere. (Hope this helped!)

Explanation:

You might be interested in
¿sabes cual es la concentración de azúcar en un refresco de un litro?​
Grace [21]
“Esto quiere decir que en una lata de 330 ml tiene alrededor de 36 gramos de azúcar, mientras que una botella de 1 l tendrá 110 gramos”

110 gramos
8 0
3 years ago
1. How many grams are there in 7.5 x 1023 molecules of H2SO4?
Karo-lina-s [1.5K]

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×10^{23} molecules of H_{2} SO_{4}?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×10^{23}

∴\frac{7.5*10^{23} }{6.02*10^{23}}=1.25 mol(2d.p.)

Lastly, find the grams using the formula M= \frac{m}{n}

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

M= \frac{m}{n} (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \frac {molecular mass} {6.02*10^{23}} = moles

5 0
3 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
The Reaction
Effectus [21]

Answer:

Explanation:

From the information given:

We can say that the rate of reaction is utilized to decide the reaction speed, and it is subject to the rate constant.

The power of concentration related to the rate equation can be said to be the order of the reaction.

For zero-order reaction: it is the reaction whose rate is free and not dependent on the reactant's concentration.  

Concentration-time reaction is given as;

\mathbf{[A] = [A_o] -kt ---- (1)}

where;

t = time

k = rate constant

A_o = initial concentration of reactant

Thus, the plot between [A] and t needs to be a straight line.

On the other hand, The First order reaction is the reaction whose rate is straightforwardly corresponding to the reactant's concentration.  

Its concentration-time relation can be expressed as,

\mathbf{In([A])= In ([A_o])-kt   ---- (2)}

t = time

k = rate constant

[A_o] = initial concentration of the reactant

Then, the plot between [A] & t requires to be a straight line.

Presently, the plot between ln([A]) vs time appears to be in a straight line with the slope of the line equivalents to the rate constant (k).

hence,

slope = -k

Then;

\mathbf{k = -slope  ---- (3)}

Now; to discover the activation energy we need to utilize Arrhenius relation which is given as,

\mathbf{In(k) = In(K_o) - \dfrac{E_o}{RT}  ---- (4)}

From the above equation;

k_o = arrhenius parameter

Ea = activation energy

R = 8.314 J/mol.K

T = temperature in Kelvin

From the data given  for concentration vs time;

t[min]      Ca(mol/L)

0                      2

5                     1.6

9                     1.35

15                   1.1

22                    0.87

30                    0.7

40                    0.53

60                    0.35

a)

Since we can deduce the order of the reaction,

Let's assume that it is a zero-order reaction, Thus, the plot of Ca vs t can be seen in the first image attached below;

From the diagram, it is clear and obvious that it is NOT a straight line.

Thus, we conclude that this order is NOT a zero-order.

However, let also assume that order is first order,

Now, from the second diagram showing the plot of ln(Ca) vs t, we can deduce that it is a straight line which implies that it is the order of the reaction is first order.

Therefore, the equation for the first order is given as;

\mathbf{In([A]) = In ([A_o])- kt}

Recall that: the slope of the ln(A) v/s time will result in a rate constant,

Thus, from the graph we have;

slope = -0.0289 mol/L.min and:

slope = - k

Hence;

rate constant = k = 0.0289 mol/L.min and the order = 1st order

b)

On the off chance that we need to take more data points, we will like to take the data point in the scope of 40 min to 60 min time interval, on the grounds that the significant deviation is seen there. more information focuses will imply more accuracy.

8 0
3 years ago
How many moles of sulfur atoms are in 9.9 moles of Ag2S
GarryVolchara [31]

Answer:

9.9 moles of Ag₂S contain 9.9 moles of sulfur.

Explanation:

Given data:

Number of moles of Ag₂S = 9.9 mol

Number of moles of Sulfur = ?

Solution:

One mole of Ag₂S having 1 mole of sulfur.

In 9.9 moles:

9.9 moles × 1 = 9.9 moles

So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.

6 0
3 years ago
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