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3 years ago

Which statement best describes weather?

Chemistry

1 answer:

Hatshy [7]3 years ago

7 0

Answer:

Weather is describes as the term of the temperature, humidity, wind velocity, precipitation, and barometric pressure. It usually happens in the troposphere, or lower atmosphere. (Hope this helped!)

Explanation:

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If acid gets on your skin or clothes, wash at once with?

ICE Princess25 [194]

water t because washing with sulfuric acid wouldn't actually get any of the acid off of you, same with oil, just soothe it momentarily and stop burning of the skin by creating a barrier to the acid. If you wash with soap it will burn even more by activating some enzymes in the acid (depending on kind of acid) so washing with water is most practical because it gets all of the acid off immediately to stop more burns from occurring. I would recommend washing with water and then pouring oil onto the burn, to create a barrier.

6 0

3 years ago

How many atoms and elements are there in C2H5OH

Hatshy [7]

Total atoms is 9 ( 2 carbon atoms, 5 hydrogen atoms, 1 oxygen atom and 1 hydrogen atom = 9 atoms)

Element is 3 ( Carbon, Hydrogen and Oxygen)

6 0

3 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

3 years ago

Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.

Arada [10]

Answer:

X = 7

Explanation:

4 0

2 years ago

Why was the line of best fit method used to determine the experimental value of absolute zero?

BartSMP [9]

Answer:

Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.

Explanation:

Charle's Law for ideal gases states that, at constant pressure, the temperature and the volume of a sample of gas are protortional.

$\dfrac{V}{T}=k\\\\V=kT$

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.

When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left 273.15ºC.

Meaning that the Volume at 273.15ºC is zero.

You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (absolute zero) as the minimum possible volume is zero.

3 0

3 years ago