D. Changes
Hope this helps :)
Answer:
Percent ionic character of HI bond is 4.91%.
Explanation:
<h3>
Given Data:</h3>
Measured Dipole = 0.380D
bond distance = d = 161pm = 1.61*10^-8 cm
<h3>
Calculation:</h3>
% ionic character is determined by following equation:
% ionic= (dipole measured/dipole calculated)*100
Now,

(In above step 3*10^8 is multiplied to convert coulomb into esu)

As,

So,

Now we can % ionic character using above equation:
%ionic=(0.380D/7.728D)*100
% ionic character=4.91%
1. exercise because you are using exercise to affect the amount of concentration. 2. concentration because concentration is what is being measured
Answer:
friction, conduction, and induction
Explanation: