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Travka [436]
2 years ago
8

Two solutions are mixed, bringing together ions of Na+, PO43−, V3+, and Cl−. Use the solubility rules to identify the compositio

n of the salt that precipitates out of the solution.
Chemistry
1 answer:
Shtirlitz [24]2 years ago
5 0
What can you conclude about the father based on this passage? Check all that apply.
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What is the only intermolecular force present in nonpolar compounds?
Anvisha [2.4K]
Answer: London dispersion forces
3 0
2 years ago
Does anyone know the answers for these
Alexeev081 [22]

Answer: 1. 0.045moles

2.  2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

1. \text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles

2. Mass of C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g

4 0
2 years ago
8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?<br>Fe + O2 → Feo​
krek1111 [17]

Answer:

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

             FeO       :       O₂

                2         :        1

                0.5      :      1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.

8 0
2 years ago
Soluble ionic compounds that dissociate naerly completely when dissolved are classified as _______.
Anettt [7]

The answer is D. Strong electrolytes

Strong electrolyte is a solute or solution that completely or almost  completely dissociates when in solution. These are good conductors of electricity only  when in molten/aqueous solution.

Strong electrolyte(aq) → Cation+(aq) + Anion−(aq)


6 0
2 years ago
How many kL does a 9.51 ´ 109 cL sample contain?
elena-14-01-66 [18.8K]

Answer:

9.51 × 10⁴ kL

Explanation:

Step 1: Given data

Volume of the sample (V): 9.51 × 10⁹ cL

Step 2: Convert "V" to liters

We will use the conversion factor 1 L = 100 cL.

9.51 × 10⁹ cL × (1 L / 100 cL) = 9.51 × 10⁷ L

Step 3: Convert "V" to kL

We will use the conversion factor 1 kL = 1000 L.

9.51 × 10⁷ L × (1 kL / 1000 L) = 9.51 × 10⁴ kL

9.51 × 10⁹ cL is equal to 9.51 × 10⁴ kL.

4 0
2 years ago
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