Tan^2 x - Tan^ x sin^2 x
= tan^2x ( 1 - sin^2 x)
= tan^2 x * cos^x
= sin^2 x * cos^2 x
----------------------
cos^2 x
= sin^2 x
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
Answer:
Step-by-step explanation:
6x-12y
trust me
No bucease it has a negative on the 11 and the other one don’t
