Speed because speed is key
Answer:
-13.51
Step-by-step explanation:
work out the difference (increase) between the two numbers you are comparing. Then: divide the increase by the original number and multiply the answer by 100. % increase = Increase ÷ Original Number × 100.,
so, -13.51
Answer:
I'm really sorry I can't tell you the answer because you have to measure the angle by yourself using a protractor. But I gave you information about types of angles if you got the degree of angles ( e.g 90 degrees). Hope it helped.
Step-by-step explanation:
acute angle-an angle between 0 and 90 degrees
right angle-an 90 degree angle
obtuse angle-an angle between 90 and 180 degrees
straight angle-a 180 degree angle
Answer:

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel
And the anfle is approximately 
Step-by-step explanation:
For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.
a=[1,2,-2], b=[4,0,-3,]
The dot product on this case is:

Since the dot product is not equal to zero then the two vectors are not orthogonal.
Now we can calculate the magnitude of each vector like this:


And finally we can calculate the angle between the vectors like this:

And the angle is given by:

If we replace we got:

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel
And the anfle is approximately 
Express in simplest a+bi form: Square root of 1b + Square root of -1b

Lets simplify 
We know 

We cannot simplify 


So a + ib form is 