Answer:
7
Step-by-step explanation:
1/2(x)=7/2
divide both sides by 1/2
x=
÷
x=
·
x=14/2=7
The general equation for slope-intercept form is y = mx + b, where m = the slope of the equation, b = the y intercept, and x and y are your variables (and the coordinate points on the graph).
Remember that for parallel lines, the slope, m, is the same for both equations. The equation you're given, y = 2x - 2, is already in slope-intercept form and the 2 in front of x is m, your slope. That means for whatever equation we come up with, m has to be 2.
So far we know the equation for our parallel line is y = 2x + b. How do we figure out b? Plug in the (x, y) coordinate you're given, (1, 1) and solve for b:

Now we know b = -1. Put that into our y = 2x + b equation to get the final equation of your parallel line:
Your final answer is y = 2x - 1.
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
Yup its 53 Degrees you got it right :)
Answer:
(1,6) & (7,0)
Step-by-step explanation:
y = -x + 7
y = -0.5(x - 3)² + 8
To solve the system, solve these two equations simultaneously
-x + 7 = -0.5(x - 3)² + 8
-x + 7 = -0.5(x² - 6x + 9) + 8
-x + 7 = -0.5x² + 3x - 4.5 + 8
0.5x² - 4x + 3.5 = 0
x² - 8x + 7 = 0
x² - 7x - x + 7 = 0
x(x - 7) - (x - 7) = 0
(x - 1)(x - 7) = 0
x = 1, 7
y = -1 + 7 = 6
y = -7 + 7 = 0
(1,6) (7,0)
Since the system has two distinct solutions, the line and the curve meet at two distinct poibts9: (1,6) & (7,0)