Answer:
The number of boxes of candy sold is 4
The number of rolls of wrapping paper sold is 10
Step-by-step explanation:
Let x = number of boxes of candy that was sold.
Let y = number of rolls of wrapping paper was sold.
The candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. This means that x boxes of candy and y rolls of wrapping paper will be sold for
$(8x + 6y)
If you have sold 14 items, and collected 92 dollars, this means that
x + y = 14
8x + 6y = 92 - - - - - - -1
Substituting x = 14 - y into equation 1, it becomes
8(14-y) + 6y = 92
112 - 8y + 6y = 92
- 8y + 6y = 92 - 112
-2y = -20
y = 20/2 = 10
x = 14 - y
x = 14 - 10
x = 4
The number of boxes of candy sold is 4.
The number of rolls of wrapping paper sold is 10.
From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last names.
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The dot plot states that:
- 2 students have 4 vowels in their first and last name.
- 3 students have 5 vowels.
- 8 students have 6 vowels.
- 9 students have 7 vowels.
Then:
- Total of 2 + 3 + 8 + 9 = 22 students.
- 3 + 8 + 9 = 20 have or more vowels.
90.91% of the students have 5 or more vowels in their first and last names.
A similar problem is given at brainly.com/question/14354536
Answer:
-45
Step-by-step explanation:
(-3)(-5)(-1 - 2)
(-3)(-5)(-3)
(15)(-3)
-45
I think its b because a coefficient is a number that is placed in front of a variable and the 4 is just a constant
X - Intercept: 3x + 5y = -15
3x + 5(0) = -15
3x + 0 = -15
3x = -15
3 3
x = -5
(x, y) = (-5, 0)
Y - Intercept: 3x + 5y = -15
3(0) + 5y = -15
0 + 5y = -15
5y = -15
5 5
y = -3
(x, y) = (0, -3)
