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3 years ago

What is the third side of the triangle when the other two is 7 and 4

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

sqrt. 65

Step-by-step explanation:

assuming that it is a right angle

7^2 + 4^2 = c^2

c=sqrt. 65

SVETLANKA909090 [29]3 years ago

4 0

Answer:

6cm

Step-by-step explanation:

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Help need for test. What is the answer. There is an error in option c. It’s supposed to say line EF not line FF. Will give first

frez [133]

The answer is C I believe

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3 years ago

While visiting friends in Brookfield, Janet bought a bike lock that was marked down 20% from an original price of $8.75. If the

Shtirlitz [24]

Answer:

7.49

Step-by-step explanation:

Well first you have to find how much the bike lock cost.

8.75 x 0.2

1.75 = how much 20% of 8.75 is

8.75-1.75

7 = the cost of the bike lock with the 20% markdown

Now you have to find the sales tax.

7 x 0.07

0.49

7 + 0.49

7.49 = total cost with all the stuff

Hopefully this was helpful. There is a shorter method too tho.

3 0

2 years ago

If y = 2x 3, find the value of y when x=-3

Ivenika [448]

Y = 2x³, when x = -3

<span>y = 2*(-3)³
</span>
<span>y = 2*-27
</span>
y = -54

6 0

3 years ago

Find the Value of X. If your answer is not an integer, express it in simplest radical form.

Gennadij [26K]

For each question we must apply the Pythagorean theorem and clear the value of x.
question 5
x = root (14 ^ 2 + 16 ^ 2)
x = root (452)
x = 2raiz (113)
question 6
x = root (8 ^ 2 + 15 ^ 2)
x = 17
question 7
x = root (12 ^ 2 + 12 ^ 2)
x = root (2 * (12 ^ 2))
x = 12raiz (2)
question 8
x = root (18 ^ 2 - 9 ^ 2)
x = root (243)
x = 9raiz (3)

6 0

2 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago