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Evgen [1.6K]
3 years ago
11

What is the third side of the triangle when the other two is 7 and 4

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

sqrt. 65

Step-by-step explanation:

assuming that it is a right angle

7^2 + 4^2 = c^2

c=sqrt. 65

SVETLANKA909090 [29]3 years ago
4 0

Answer:

6cm

Step-by-step explanation:

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Step-by-step explanation:

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Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

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2 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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