I need help with this question.

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer:

x = 7.5

Step-by-step explanation:

A scale factor of 0.75 means all the dimensions are multiplied by 0.75. When the dimension 10 is multiplied by 0.75, it becomes ...

... x = 0.75 × 10 = 7.5

You might be interested in

Which of the following is a like radical to mc001-1.jpg?

mixer [17]

You haven't provided the expression or the choices, therefore, I cannot provide an exact answer.
However, I'll try to help you understand the concept so that you can solve the question you have

Like radicals are characterized by the following:
1- They both have the same root number (square root, cubic root , ...etc)
2- They both have the same radicand (meaning that the expression under the root is the same in both radicals)

Examples of like radicals:
3 $\sqrt{xyz}$ and 7 $\sqrt{xyz}$
$\sqrt[5]{x^2y}$ and 3 $\sqrt[5]{x^2y}$

Check the choices you have. The one that satisfies the above two conditions would be your correct choice

Hope this helps :)

7 0

3 years ago

Read 2 more answers

What is 12X-4y = -8 written in slope-intercept form?

qwelly [4]

Answer:

y = 3x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Given

12x - 4y = - 8 ( subtract 12x from both sides )

- 4y = - 12x - 8 ( divide all terms by - 4 )

y = 3x + 2 ← in slope- intercept form

3 0

3 years ago

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .