There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset
<h3>The doctors' mean absolute deviation on glasses</h3>
The dataset of doctor A is given as:
643 634 670 658 636 624 641 655 649 629
The dataset of doctor B is given as:
651 625 622 624 631 621 653 647 646 646
Using a statistical calculator, we have:
<u>Doctor A</u>
- Doctor A: Mean Absolute Deviation (MAD) = 11.28
- Doctor B: Mean Absolute Deviation (MAD) = 12
Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses
<h3>The variation of the two data</h3>
In a dataset, the larger the mean absolute deviations value, the larger the variation.
By comparison, 12 is greater than 11.28
Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset
Read more about mean absolute deviation at:
brainly.com/question/3250070
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