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babunello [35]
4 years ago
13

Solve for x: 2(3x + 4) - 3(x - 1) = x - 1  ​

Mathematics
2 answers:
zhannawk [14.2K]4 years ago
4 0

Answer:

x=-113

Step-by-step explanation:

2(3x+4)−3(x−1)=x−1x

Step 1: Simplify both sides of the equation.

2(3x+4)−3(x−1)=x−1x

(2)(3x)+(2)(4)+(−3)(x)+(−3)(−1)=x+−1x(Distribute)

6x+8+−3x+3=x+−x

(6x+−3x)+(8+3)=(x+−x)(Combine Like Terms)

3x+11=0

3x+11=0

Step 2: Subtract 11 from both sides.

3x+11−11=0−11

3x=−11

Step 3: Divide both sides by 3.

3x3=−113

x=−113

Answer:

x=−113

Kaylis [27]4 years ago
4 0
The answer is X= -113
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a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
Maurinko [17]

Answer:

the answer is 14

Step-by-step explanation:

Since 8 is double of four and you cant find the denominator just double 7 to get 14.

Hope this helped.

A brainliest is always appreciated.

3 0
3 years ago
Read 2 more answers
A track star in Arizona ran the 100 meter dash event is six track meets. Her average time for all six meets was 11.8 seconds. Sh
natima [27]

Answer:

A track star in Arizona running time in the last meet was 11.5 seconds.

Step-by-step explanation:

Given:

average time for all six meets = 11.8 seconds.

Time for 1st meet = 11.7 seconds.

Time for 2nd meet = 11.6 seconds.

Time for 3rd meet = 12 seconds.

Time for 4th meet = 12.1 seconds.

Time for 5th meet = 11.9 seconds.

We need to find the running time for her last meet.

Solution:

Let the running time for her last meet be 'x'.

So we can say that;

average time for all six meets is equal to sum of Time for 1st meet, Time for 2nd meet, Time for 3rd meet,Time for 4th meet, Time for 5th meet and time for her last meet and then divided by 6.

framing in equation form we get;

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Now Multiplying both side by 6 we get;

\frac{59.3+x}{6}\times 6= 11.8\times6\\\\59.3+x=70.8

Now Subtracting both side by 59.3 we get;

59.3+x-59.3=70.8-59.3\\\\x=11.5 \ s

Hence A track star in Arizona running time in the last meet was 11.5 seconds.

7 0
3 years ago
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maria [59]
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4 0
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inysia [295]
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12oz *\frac{5}{2}= 30 oz  
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8 0
3 years ago
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