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3 years ago

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A line passes through the point (8,-9) and has a slope of -5/2. Write an equation in slope intercept form for this line.

1 answer:

noname [10]3 years ago

4 0

Answer:

y = - $\frac{5}{2}$ x + 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{5}{2}$ , then

y = - $\frac{5}{2}$ x + c ← is the partial equation

To find c substitute (8, - 9) into the partial equation

- 9 = - 20 + c ⇒ c = - 9 + 20 = 11

y = - $\frac{5}{2}$ x + 11 ← equation of line

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Answer:

$f''(x)=f''(-x)$

Step-by-step explanation:

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Applying the chain rule again we have:

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Step-by-step explanation:

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In circle C with mZBCD = 106 and BC = 6 units find area of sector BCD.

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Step-by-step explanation:

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