2 moles of NaOH dissolved in 1 litre of solution is the solution with more concentration.
Answer: Option A
<u>Explanation:</u>
Concentration of solution is the measure of the amount of solute dissolved in the solvent of the solution. So this is measured using the molarity of the solution. Molarity is determined as the number of moles of the solute present in the given amount of solvent.
In this present case, the option A gives the molarity of 2 M as
But the second option, mass of NaOH is given. So we have to determine the molarity. First we have to find the molar mass of NaOH. We know that 1 mole of NaOH will contain 40 g/mole.
1 g of NaOH = 40 g of NaOH
1 g of NaOH = 1/40 moles
So 2 g of NaOH will contain which is equal to 0.05 moles of NaOH.
Thus, the molarity of 2 g of NaOH will be
Molarity = =0.05 M
Thus, the option A is having higher concentration as the molarity is more for 2 moles of NaOH dissolved in 1 l of solution.
Answer:
- % Cobalt (II) Nitrate = 30.62%
Explanation:
To calculate mass percent, first we need to <u>calculate the total mass of the mixture</u>:
- Mass Water ⇒ 0.350 kg Water = 350 g water
- Mass Ammonia⇒We use ammonia's molar mass⇒5.4 mol * 17 g/mol = 91.8 g
- Mass cobalt (II) nitrate ⇒ 195.0 g
Total Mass = Mass Water + Mass Ammonia + Mass Cobalt Nitrate
- Total Mass = 350 g+ 91.8 g+ 195 g = 636.8 g
To calculate each component's mass percent, we divide its mass by the total mass and multiply by 100:
- % Water ⇒ 350/636.8 * 100% = 54.96%
- % Ammonia ⇒ 91.8/636.8 * 100% = 0.14%
- % Cobalt (II) Nitrate ⇒ 195/636.8 * 100% = 30.62%
Answer:
When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate.
When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose
When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid
Explanation:
When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate. Because always a salt is more soluble in water than its acid (Solubility of propionic acid is 0,37g/mL and of sodium propionate is 1g/mL).
When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose because cyclohexane is made from petroleum and its polarity is very low (cyclohexane is insoluble in water and solubility of glucose is 0,91g/mL).
When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid because an acid has a medium-high solubility in water but, again, an alkane derived from petroleum has very low solubility in water (hydrochloric acid has a solubility of 0,823g/mL and ethyl chloride is insoluble in water).
I hope it helps!
Explanation:
<u>Physical properties of ZBr₂</u>
The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:
- it is a hard solid usually with high melting points or a liquid with high boiling points.
- Soluble in water and insoluble in non-polar solvents.
- It can conduct electricity in aqueous solutions or in molten form.
- it will undergo a fast reaction.
<u>Z is a metal</u>
To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.
<u>Formula of the oxide</u>
ZO
Z 0
+2 -2
It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.
Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.
Learn more:
ionic compounds brainly.com/question/6071838
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Answer:
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