Answer: The new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 0.732 atm
= final pressure of gas = ?
= initial volume of gas = 6.87 L
= final volume of gas = 9.22 L
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:


Thus the new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm
<span>Calculate the standard entropy change for the dimerization of NO2: 2NO2(g)→N2O4(g)at 298 K, if
Sâ—¦ â†Hâ—¦f J/K·mol
NO2(g) 240.06 33.18
N2O4(g) 304.29 9.16
Answer in units of J/K·mol
AP Chemistry - DrBob222 Tuesday, October 29, 2013 at 8:53pm
See your other posts below.
AP Chemistry - fg Monday, April 4, 2016 at 4:19pm
dg4354
2242342
1111
AP Chemistry - Eman Monday, April 25, 2016 at 11:19am
-175.8 j/k.mol</span>