I don’t know but are you on cbse or what plz answer
A) molar mass H₂ = 2.0 g/mol
m = n * mm
m = 15.0 * 2.0
m = 30.0 g of H₂
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b) molar mass N₂ = 28.0 g/mol
m = n * mm
m = 3.5 * 28.0
m = 98.0 g of N₂
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c) molar mass of NaOH = 40.0 g/mol
m = n * mm
m = 2.69 * 40.0
m = 107.6 g of NaOH
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hope this helps!
The mass percent of sulfurous acid in the new solution : 38.9%
<h3>Further explanation</h3>
<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>
<em />
solution 1
composition :
solution 2(new solution)
composition :
- Total mass of new solution after water evaporated
- %mass of acid in a new solution
Protons, neutrons..................................
The reaction is exothermic and the product can be clearly indentified .the experement illutrate the difference is reactive between zinc and lead oxide and hence the idea of competition reaction.