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Degger [83]
3 years ago
9

Which one of the following ionic solids would have the largest lattice energy?! A) CaCl2 B) CaBr2 C) Csi D) NaCl E) NaF

Chemistry
1 answer:
Kisachek [45]3 years ago
4 0
The answer would be d
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Which of the following is the part of the experiment that is the change that is observed or measured?
solong [7]

Answer:

The independent variable is the variable that is deliberately changed by the scientist. The dependent variable is the one observed during the experiment. The dependent variable is the data we collect during the experiment.

Explanation:

7 0
3 years ago
If 348 grams of Mg(OH)2 reacts with excess HCl (this is CL chlorine, not C and I), how many moles of MgCl2 (this is CL chlorine,
avanturin [10]

Answer:

moles MgCl₂ = 5.97 moles

Explanation:

First, let0s write the overall reaction that is taking place here:

Mg(OH)₂ + HCl ----------> MgCl₂ + H₂O

Now, we need to balance this reaction:

Mg(OH)₂ + 2HCl ----------> MgCl₂ + 2H₂O

Now, the exercise already stated that the HCl is in excess, so we can assume the magnesium hydroxide is the limiting reactant. If this is true, then, to get the moles of MgCl₂ produced, all we need to do is calculate the moles of Mg(OH)₂ that reacted, using the following expression:

moles = mass / MM

The atomic weights for Mg, O and H are:

Mg: 24.305 g/mol;  H: 1 g/mol;  O = 15.999 g/mol

Let's determine the molar mass of Mg(OH)₂:

MM = 24.305 + (2 * 15.999) + (2 * 1) = 58.303 g/mol

Now, let's determine the moles:

moles = 348 g / 58.303 g/mol = 5.97 moles of Mg(OH)₂

As we can see in the overall reaction, there is a mole ration between Mg(OH)₂ and MgCl₂ of 1:1, that's why we can conclude that the moles of Mg(OH)₂ would be the same moles of MgCl₂:

<h2>moles Mg(OH)₂ = moles MgCl₂ = 5.97 moles</h2>

Hope this helps

4 0
2 years ago
A sample of cl2 gas has a volume of 15.0 l at a pressure of 1.50 atm and a temperature of 23 °c. What volume, in liters, will th
olganol [36]

Given: Initial volume of CO_{2} gas= 15.0 L

Pressure=1.50 atm

Temperature=23°C

Use ideal gas equation as follows:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature in Kelvin.

First convert the given temperature in Kelvin.

0°C=273.15 K

Thus, 23 °C=296.15 K

Rearranging ideal gas equation to calculate the value of nR as follows:

nR=\frac{PV}{T}=\frac{(1.50 atm)(15.0 L)}{(296.15 K)}=0.0760 atm LK^{-1}

Now, final pressure is 3.50 atm and temperature is 286°C, converting the temperature into Kelvin,

0°C=273.15 K

Thus, 286 °C=559.15 K

Volume can be calculated using the ideal gas equation as follows:

V=\frac{nRT}{P}

Putting the value of given pressure and temperature and the above calculated value of nR,

V=\frac{(0.0760 atmLK^{-1})(559.15 K)}{(3.50 atm)}=12.14 L

Therefore, volume of CO_{2} at 3.50 atm and 286°C is 12.14 L.

4 0
3 years ago
Read 2 more answers
A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 14.0 mL , how many mi
STatiana [176]
To solve multiply 14 by 5%, so 14*.05=.7
So there are .7 mL of active ingredient in this cough syrup
7 0
3 years ago
Read 2 more answers
Help please which substance is not a compound​
Nastasia [14]

Magnesium is not a compound

4 0
2 years ago
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