Answer:
A
Step-by-step explanation:
It is linear because it is a pattern of adding 1 and not quadratic for there is no squaring. It is no exponential because the ratio stays the same.
![Rewrite the expression 6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$](https://tex.z-dn.net/?f=Rewrite%20the%20expression%20%206j%5E2%20-%204j%20%2B%2012%24%20in%20the%20form%20%24c%28j%20%2B%20p%29%5E2%20%2B%20q%24%2C%20where%20%24c%24%2C%20%24p%24%2C%20and%20%24q%24%20are%20constants.%20What%20is%20%24%5Cfrac%7Bq%7D%7Bp%7D%24)
The ratio of
= - 34
How to solve such questions?
Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.
Completing the square is a method that is used for converting a quadratic expression of the form
to the vertex form
. The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square:
, such that the left side is a perfect square trinomial
= ![$6(j^2 - \frac{2}{3} j )+12$](https://tex.z-dn.net/?f=%246%28j%5E2%20-%20%5Cfrac%7B2%7D%7B3%7D%20j%20%29%2B12%24)
=
(Completing Square method)
=![6( j- \frac{1}{3} )^{2} + \frac{34}{3}](https://tex.z-dn.net/?f=6%28%20j-%20%5Cfrac%7B1%7D%7B3%7D%20%29%5E%7B2%7D%20%20%2B%20%20%5Cfrac%7B34%7D%7B3%7D)
On comparing with the given equation we get
p = -
and q = ![\frac{34}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B34%7D%7B3%7D)
∴
= ![\frac{\frac{34}{3} }{\frac{-1}{3} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B34%7D%7B3%7D%20%7D%7B%5Cfrac%7B-1%7D%7B3%7D%20%7D)
= - 34
Learn more about completing the square method here :
brainly.com/question/26107616
#SPJ4
Answer: 3000 stamps
Step-by-step explanation:
Given
Chris and Josh have 1800 stamps
Josh and Jessica have 2200 stamps
Jessica and Chris have 2000 stamps
Suppose Chris, Josh, and Jessica have
stamps
![\therefore x+y=1800\quad \ldots(i)\\\Rightarrow y+z=2200\quad \ldots(ii)\\\Rightarrow z+x=2000\quad \ldots(iii)\\\text{Add (i), (ii), and (iii)}\\\Rightarrow 2(x+y+z)=1800+2200+2000\\\Rightarrow x+y+z=3000](https://tex.z-dn.net/?f=%5Ctherefore%20x%2By%3D1800%5Cquad%20%5Cldots%28i%29%5C%5C%5CRightarrow%20y%2Bz%3D2200%5Cquad%20%5Cldots%28ii%29%5C%5C%5CRightarrow%20z%2Bx%3D2000%5Cquad%20%5Cldots%28iii%29%5C%5C%5Ctext%7BAdd%20%28i%29%2C%20%28ii%29%2C%20and%20%28iii%29%7D%5C%5C%5CRightarrow%202%28x%2By%2Bz%29%3D1800%2B2200%2B2000%5C%5C%5CRightarrow%20x%2By%2Bz%3D3000)
Thus, all three have 3000 stamps
Answer:
First number=6
Second number=14
Step-by-step explanation:
Let the first number be x
So the second number is x+8
So the sum of the two is
X+x+8=20
2x+8=20
2x=20-8
2x=12
X=12/2
=6
The second number will x+8
So 6+8=14
First number=6
Second number=14
Answer:
For the first question, the answer is 4/3. For the second it is 16.
Step-by-step explanation:
I just took the quiz! Can I please have Brainliest? Hope this helped!