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disa [49]
3 years ago
7

What is the predicited order of first ionization energies from highest to lowest for lithium sodium potassium and rubidium

Chemistry
1 answer:
velikii [3]3 years ago
4 0

The predicted order of ionization energies is Li > Na > K > Rb

<em>Atomic size increases as you go down a Group</em> (see image). We are adding electrons to increasingly larger shells.

The valence electrons are further from the attraction of the nucleus, so they are less tightly held.

Thus, <em>Li has the highest ionization energy</em> and <em>Rb the lowest</em>.

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Calculate [H+] for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral.
vesna_86 [32]

Answer:

<em>Part A: </em>10.7.

<em>Part B: </em>2) the solution is basic.

<em>Part C: </em>5.9.

<em>Part D: </em>1) the solution is acidic.

<em>Part E: </em>8.1.

<em>Part F: </em>2) the solution is basic.

Explanation:

<em>Part A [OH−]= 4.5×10−4 M . Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>[OH⁻] = 4.5×10⁻⁴ M. </em>

<em>∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(4.5×10⁻⁴  M) = 2.22 × 10⁻¹¹ M.</em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(2.22 × 10⁻¹¹) = 10.65 ≅ 10.7.</em>

<em></em>

Part B 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  

The solution is basic, because the pH is higher than 7.

<em>Part C [OH⁻]= 7.7×10⁻⁹ M . Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>[OH⁻] = 7.7×10⁻⁹ M. </em>

<em>∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(7.7×10⁻⁹ M) = 1.29 × 10⁻⁶ M.</em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(1.29 × 10⁻⁶) = 5.88 ≅ 5.9.</em>

<em>Part D 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  </em>

The solution is acidic, because the pH is lower than 7.

<em>Part E A solution in which [OH−] is 140 times greater than [H+]. Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>∵  [OH⁻] = 140[H₃O⁺]</em>

<em>∴ [H₃O⁺](140[H₃O⁺]) = 10⁻¹⁴. </em>

<em>∴ 140 [H₃O⁺]² = 10⁻¹⁴. </em>

<em>[H₃O⁺]² = 10⁻¹⁴/ 140 = 7.14 x 10⁻¹⁷.</em>

<em>∴ [H₃O⁺] = √(7.14 x 10⁻¹⁷) = 8.45 x 10⁻⁹ M.</em>

<em></em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(8.45 x 10⁻⁹) = 8.07 ≅ 8.1.</em>

<em>Part F 1) the solution is acidic 2) the solution is basic 3) the solution is neutral</em>

<em></em>

The solution is basic, because the pH is higher than 7.

3 0
3 years ago
A strand of hair is approximately 50 μm thick. If the diameter of an atom is 1 × 10-10 m, how many atoms thick is a strand of ha
Kazeer [188]

Thickness of strand hair = 50 μm

Diameter of an atom  = 1 \times 10^{-10} m

Now, with the help of conversion factors, convert thickness in micrometer into meter i.e. 1 micrometer = 10^{-6}m

So, thickness of strand hair =50 μm= 50 \times 10^{-6} m

Therefore,

number of atoms thick is a strand of hair =  50 \times 10^{-6}m\times \frac{1 atom}{1 \times 10^{-10}m}

= 50\times 10^{4}atoms

Hence, number of atoms is 50\times 10^{4}atomsthick is a strand of hair.


6 0
3 years ago
Read 2 more answers
The body's nervous system is made up of the brain,the spinal cord, the retina ,and many other nerves. The circulatory system is
posledela
<h2>O sistema nervoso do corpo é formado pelo cérebro, pela medula espinhal, pela retina e por muitos outros nervos.</h2><h2> O sistema circulatório é constituído pelo coração, artérias, veias e capilares.  </h2>
8 0
3 years ago
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Wes melted some cheese over some tortilla chips to make nachos.
natima [27]

Answer:

a

Explanation:

Because the mass would stay the same and the flavor did not change and neither did the color so the shape is the only thing that changed

4 0
3 years ago
14. Which group of diamagnetic transition metals exhibits trends in density and melting points that don't match the same trends
inn [45]

Answer:

Group 12

Explanation:

Group 12 transition metals are diamagnetic. They behave properties that distinguish them. They naturally have twelve electrons hence their outermost shell is fully filled.

Transition metals have high densities which increases down the group. However, the increase in density of transition elements of group 12 varies with temperature at a rate that is quite different from other transition elements. Hence the differences in the value of melting points and density changes by only a very small amount as you come down group 12 compared to other groups of transition elements.

6 0
3 years ago
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