Answer:
n₂ = 2.55 mol
Explanation:
Given data:
Initial number of moles = 0.758 mol
Initial volume = 80.6 L
Final volume = 270.9 L
Final number of moles = ?
Solution:
Formula:
V₁/n₁ = V₂/n₂
V₁ = Initial volume
n₁ = initial number of moles
V₂ = Final volume
n₂ = Final number of moles
now we will put the values in formula.
V₁/n₁ = V₂/n₂
80.6 L / 0.758 mol = 270.9 L/ n₂
n₂ = 270.9 L× 0.758 mol / 80.6 L
n₂ = 205.34 L.mol /80.6 L
n₂ = 2.55 mol
Answer:
The water will absorb 1004.16 Joule of heat
Explanation:
Step 1: Data given
Mass of the metal = 58.00 grams
Temperature of the metal = 100.00 °C
Mass of water = 60.00 grams
Temperature of water = 18.00 °C
Final temperature = 22.00 °C
Specific heat of water = 4.184 J/g°C
Step 2: Calculate the amount of heat absorbed by the water in joules
Q = mass *specific heat *ΔT
⇒ with Q = the heat absorbed by water
⇒ with mass of water = 60.00 grams
⇒ with specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C
Q = 60.00 * 4.184 J/g°C * 4.0 °C
Q = 1004.16 J
The water will absorb 1004.16 Joule of heat
Answer:
The density of water
.
Explanation:
Density of water = 1.00 g/mL
1 lb = 453.592 g



Density of the water in
:


The density of water
.
Answer:
Sr would be the limiting reactant
5 moles
Explanation:
Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.
Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.
Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.
From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.
When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.
For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.