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Ann [662]
3 years ago
5

Find the molar mass of 2Cu (NO3)2​

Chemistry
1 answer:
8090 [49]3 years ago
7 0

Answer:

187.5558 mol

Explanation:

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Which of these carbohydrates is a monosaccharide maltose fructose cellulose or lactose
GenaCL600 [577]
Your answer should be fructose! :)

7 0
2 years ago
Read 2 more answers
Human reaction time is usually about 0.18 s. If your lab partner holds a ruler between your finger and thumb and releases it fro
Marizza181 [45]

Answer:

–0.16 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 0.18 s

Acceleration due to gravity (g) = –9.81 m/s²

Height (h) =?

We can obtain how far the ruler will fall by using the following equation:

H = ½gt²

H = ½ × –9.81 × 0.18²

H = ½ × –9.81 × 0.0324

H = –0.16 m

Thus, the ruler will fall –0.16 m before you will catch it.

7 0
2 years ago
Why is the Chemical symbol for lead Pb?? ^__^ i HATE the perdiotic** table!!
tatuchka [14]
Cause latin name of Pb is plumbum.
The same K - potassium - latin name is kalium.
3 0
3 years ago
A chemical reaction is occurring inside a beaker and the temperature of the beaker is monitored. What would the contents of the
Archy [21]

<u>Answer:</u>

<em>The system is the Answer </em>

<em></em>

<u>Explanation:</u>

System is the region which is taken into consideration.

While we perform a chemical reaction the system is the substance taken in the container.

So, A thermodynamic system is the amount of matter or the region in universe which is under the study.

The region outside the beaker are called as surroundings.

The beaker (the surface which separates the system from its surroundings) is said to be the boundary

System + surroundings = universe

3 0
3 years ago
A 45.0 g sample of a metal at 85.6 °C is placed in 150.0 g of water at 24.6 °C. The final temperature of the system is 28.3 °
earnstyle [38]

Answer:

904.014 j/kgk

Explanation:

Mass of metal = 45g

Temperature of metal = 85.6°

Mass of water = 150

Temperature of water = 24.6

Final temperature of system = 28.3

Heat lost by metal = Heat gained by water

m1 * c1 * dt = m2 * c2 * dt

Q = quantity of heat

Q = m*c*dt

dt = change in temperature

dt of water = 28.3 - 24.6 = 3.7

dt of metal = 85.6 - 28.3 = 57.3

Specific heat capacity of water, c = 4200

(45 * 10^-3) * c * 57.3 = (150 * 10^-3) * 4200 * 3.7

2.5785c1 = 2331

c1 = 2331 / 2.5785

= 904.01396

= 904.014 j/kgk

3 0
2 years ago
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