Answer:
2.04
Step-by-step explanation:
Answer:
4. x= 18
Step-by-step explanation:
We solve the problem like this:
Since 3 is proportional to 6 and 9 is proportional to x, we set up a proportion.
3/9 = 6/x
We then use cross-multiplication to solve for x.
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
(A)
1,4
1,3
1,2
1,1
2,1
2,2
2,3
2,4
3,1
3,2
3,3
3,4
4,1
4,2
4,3
4,4
5,1
5,2
5,3
5,4
6,4
6,3
6,2
6,1
(B)
3%
(C)
I'm not sure about the answer for C, Sorry. Hope this helps!
(x-4)^2+(y-0)^2=3^2 is the answer