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malfutka [58]
3 years ago
12

What are the solutions to the equation?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

x = -4 ±3

x = -7,-1

Step-by-step explanation:

x^2 + 8x     = -7

1/2 B ^ 2 = 16

x^2 + 8x  + 16    = 16 -7

(x + 4) ^2 = 9

x + 4 = ±3

x = -4 ±3

x = -7,-1

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What is 6 x 10(2) aka 6 x 10 to the second power
Crank

Answer:

3600

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Look at the graph shown:
NNADVOKAT [17]
We are going to base the answer off of the y=mx+b form where m represents slope and b represents the y-intercept.

First, we know that b must be -1 because the line hits the y-axis when y is -1
So this leaves us with either the first or second choice

Then we choose two points to find the slope. I am using (0,-1) and (1,2). If you count the boxes, the y-value increases by 3 as the x-value increases by 1. So the slope is 3/1 or 3.

So then we know the answer is y=3x-1

Hope this helps 
4 0
3 years ago
Write a system of equations to describe the situation below, solve using elimination or substitution.
tangare [24]
X= mountain dew    y= coke

-(5x+5y=1160)
8x+5y=1523

-5x-5y=-1160
+
8x+5y=1523

<u>3x</u>=<u>363
</u><u />3      3

x=121 g of sugar in Mt. Dew

8x+5y=1523 plug in 3 in x

24+5y-24= 1523-24

<u>5y</u>= <u>1499
</u>5       5

y= 299.8 grams of sugar in coke



4 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
So I'm on changing units so I need help so what is 360cm=m
zlopas [31]
The answer is 3.6 meter
7 0
2 years ago
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