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malfutka [58]
3 years ago
12

What are the solutions to the equation?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

x = -4 ±3

x = -7,-1

Step-by-step explanation:

x^2 + 8x     = -7

1/2 B ^ 2 = 16

x^2 + 8x  + 16    = 16 -7

(x + 4) ^2 = 9

x + 4 = ±3

x = -4 ±3

x = -7,-1

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An average score of 90 or above in an English course receives an A grade. A student has grades of 81, 87, 94, 93 on four tests.
Inessa05 [86]

Answer:

95>=X <=100. More or equal to 95 or equal or less than 100.

Step-by-step explanation:

The Total of the first score is needed first

81+87+ 94+93=355

The total of this score

Let X be the 5TH score we are looking for

(355+ X)/5= 90

355+X= 450

X= 450-355

X= 95 the person needs to sore between 95 and 100 ( which is the highest possible score).

5 0
3 years ago
What is the length of side x in the above right triangle​
nataly862011 [7]

Answer:

its answer will be 9.first by using phythagorus theorem h^2=p^2+b^2'then h=15,p=12and b=x. again by putting the values of h ,p and b we get ,(15)^2=(12)^2+x^2. 225=144+x^2, x^2=225-144, x^2=81,x=√81,x=9 answer

7 0
3 years ago
XZ=n, WZ=2x-5, and the perimeter of ΔXWZ is 20. What is the value of n?
Sergio039 [100]

Answer:

d.

Step-by-step explanation:

Since it's an isosceles triangle, WX=WZ= 2n-5

Perimeter = n + (2n-5) + (2n-5)

= 5n - 10

The Perimeter is given to be 20

5n - 10 = 20

5n = 30

n = 6

3 0
2 years ago
i am a decimal number less than 1. the digit in my tenths place is an even prime number. my hundredths digit is twice my tenths
tankabanditka [31]

Answer:

.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How do you know what angle degree goes on each corner?
Dahasolnce [82]

Let'sSo, we gave 2 parallel lines and 2 transversals, we have to match the angles.

Let's start with angle b,

\begin{gathered} b+65=180\text{ (angles in a straight line)} \\ b=180-65 \\ b=115^o \end{gathered}

Let's move on to angle e,

\begin{gathered} e=b\text{ (Vertically opposite angles)} \\ \text{but b = 115}^o \\ e=115^o^{} \end{gathered}

Let's move on to angle d,

d=110^o\text{ (V}ertically\text{ opposite angles)}

Moving to angle c, we have;

c=45^o\text{ (Vertically opposite angles)}

And, angle a;

\begin{gathered} a=b\text{ (Alternate angles)} \\ a=115^o \end{gathered}

8 0
1 year ago
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