Find the product. 1.5m6(-2m2)4

Mathematics

1 answer:

kogti [31]3 years ago

5 0

9514 1404 393

Answer:

24m^14

Step-by-step explanation:

It looks like you want to simplify ...

$1.5m^6(-2m^2)^4=(1.5)(-2)^4(m^6)(m^{2\cdot4})\\\\=(1.5)(16)m^{6+8}=\boxed{24m^{14}}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

(ab)^c = (a^c)(b^c)

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PLS HELP BRAINLIEST WILL BE AWARDED IF ANSWER IS CORRECT

Monica [59]

Answer:

AC = 18.1 cm

Step-by-step explanation:

Construct a line from point B perpendicular to the line AD and mark it as E on line AD. Now you have a right triangle ABE with AB = 16 cm and AE = AD - BC

so AE = 11 cm - 4 cm = 7 cm

You can find BE by using Pythagorean theorem

BE^2 = AB^2 - AE^2

BE^2 = 16^2 - 7^2

BE^2 = 256 - 49

BE^2 = 207

BE = 14.4 cm

Draw a line from A to C, you have a right triangle ACD with AD = 11cm and CD = BE = 14.4 cm

Using Pythagorean theorem

AC^2 = AD^2 + CD^2

AC^2 = 11^2 + 207

AC^2 = 121 + 207

AC^2 = 328

AC = 18.1 cm

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A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects

Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $p=10$ groups and on each group from $j=1,\dots,p=10$ we have $n_j$ individuals on each group we can define the following formulas of variation: