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3 years ago

Find the value of x for whichЗ(2^x-3) = 384

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

x=log2(131)

Step-by-step explanation:

3(2^x-3)=384

x=7.03342

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Solve the following inequality. 9x−2>43

kirill [66]

Answer:

x > 5

Step-by-step explanation:

Given

9x - 2 > 43 ( add 2 to both sides )

9x > 45 ( divide both sides by 9 )

x > 5

8 0

3 years ago

Mr. Rodrigo pours himself a glass of orange juice every morning. Yesterday he drank 5/6 of his glass. Today he drank 7/12 of his

bonufazy [111]

Yesterday.
Exp: if you make the denominators equal, 5/6 becomes 10/12 which is more than 7/12

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2 years ago

Simplify the sum. (4u3 + 4u2 + 2) + (6u3 – 2u + 8)

Elan Coil [88]

Answer:

$10u^{3}+4u^{2}-2u+10$ or $2(5u^{3}+2u^{2}-u+5)$

Step-by-step explanation:

we have

$(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)$

step 1

Group terms that contain the same variable

$(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)$

step 2

Combine like terms

$(10u^{3})+(4u^{2})+(-2u)+(10)$

step 3

Eliminate parenthesis

$10u^{3}+4u^{2}-2u+10$

step 4

Factor the number $2$

$2(5u^{3}+2u^{2}-u+5)$

8 0

3 years ago

Read 2 more answers

Choose the correct graph to fit the equation 3y=2x+3

Katyanochek1 [597]

Answer:

y = 2/3x + 1

Step-by-step explanation:

3y = 2x + 3 Divide all by 3

3 3 3

y = 2/3x + 1 Slope is 2/3

3 0

3 years ago

Read 2 more answers

Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?

leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

$v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\$

Step 2

find the volume of the sphere when radius= 5.1 ft

$v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\$

Step 3

Compare the Volumes to find the change

$\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06$

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

$change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet$

change=18.03 cubic feet

Have a great day.

4 0

3 years ago

Find the value of x for whichЗ(2^x-3) = 384​

Find the value of x for whichЗ(2^x-3) = 384