Answer:
11x^2+2
Step-by-step explanation:
you put the 9x^2 beside 2x^2 because they are both x^2 then the 2 will stay the same
A reasonable estimate for 8.24 divided by 4 would be 2. This would be a reasonable estimate because .24 rlly isn’t all that much so you are able to round down to 8. (Hope that’s right!)
<h3>
Answer: 10^(1/2)</h3>
When we use an exponent of 1/2, it is the same as a square root. The more general rule is

In this case, we plug in x = 10.
The use of a fractional exponent is handy when you want to deal with things like cube roots on a calculator. This is because
![\sqrt[3]{x} = x^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B1%2F3%7D)
Many calculators don't have a button labeled
but they have the button
to allow fractional exponents.
I do not know jekejejejejrjriekeje
Answer:

Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have

and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
and by evaluating in the limits we have

Hope this helps
regards