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3 years ago

If f(x) = 3x - 1 and f(x) = 3f(x) = 3, find x.

Mathematics

1 answer:

Elena L [17]3 years ago

7 0

Answer:

x = 4/3

Step-by-step explanation:

f(x) = 3x - 1

f(x) = 3

set equal

3x - 1 = 3

add 1 to both sides

3x = 4

Divide both sides by 3

x = 4/3

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How many different 2-digit numbers are there with the following property: the tenth digit is greater than the units digit?

EastWind [94]

Answer:

There is 45 different 2-digit numbers.

Step-by-step explanation:

My way is kinda dumb, but it still works. So, 2 digit numbers is from 10-99. We can start from the 10-19 first.

10, 11,12,13,14,15,16,17,18,19

We need to find the numbers that the tenth digit is greater than the units digit.

<u>10</u>, 11,12,13,14,15,16,17,18,19

Since 1 is the tenth digit, all the ones digits are all going to be bigger. Same goes with 20-29. Then you will have 2 numbers that the tenth digit is greater. My way applies when the tenth digit is only less than the ones digit, not greater. If you do this way...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

10-19: 1 number

20-29: 2 numbers

30-39: 3 numbers

40-49: 4 numbers

50-59: 5 numbers

60-69: 6 numbers

70-79: 7 numbers

80-89: 8 numbers

90-99: 9 numbers

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

So, if you add 1+2+3+4+....+9(which all of you probably memorized by now) it would be 45. The answer is 45. Hope this helped!

8 0

3 years ago

What is 10 divided by 4 ?

viktelen [127]

Answer: 10 / 4 = 2.5

7 0

3 years ago

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a family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on behalf of the family at a local benefit. What

Vesna [10]

$\dfrac{\displaystyle\binom{8}{2}}{\displaystyle\binom{12}{2}}=\\\\
\dfrac{\dfrac{8!}{2!6!}}{\dfrac{12!}{2!10!}}=\\\\\
\dfrac{8!}{2!6!}\cdot\dfrac{2!10!}{12!}=\\\\
\dfrac{7\cdot8}{2}\cdot\dfrac{2}{11\cdot12}=\\\\
\dfrac{7\cdot4}{11\cdot3}=\\\\
\dfrac{28}{33}

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3 years ago

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4 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

3 years ago

If f(x) = 3x - 1 and f(x) = 3f(x) = 3, find x.​

If f(x) = 3x - 1 and f(x) = 3f(x) = 3, find x.