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vitfil [10]
3 years ago
6

When the pressure on a solid is greatly increased, the volume of the solid shows almost no change.

Chemistry
1 answer:
Veronika [31]3 years ago
4 0

Answer:

The volume of the solid shows no change

Explanation:

Pressure only affects gaseous system. This is because the force of cohesion between the gaseous molecules are negligible(i.e very small) and their molecules are far apart hence the gaseous molecules are easily compressed. But for solid, the Particles are very close and tightly packed together with a strong force of cohesion hence pressure has no effect on it. This account for the definite shape and definite volume of solid

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1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)
Mrac [35]

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂  +  2H₂SO₄     →     2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles =  300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and  H₂SO₄.

                   H₂SO₄         :       SrCl₂

                        2             :           1

                      3.1             :         1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

3 0
3 years ago
In an experiment, zinc chlorate decomposed according to the following chemical equation.
mote1985 [20]

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of Zn(ClO_3)_2

\text{ Moles of }Zn(ClO_3)_2=\frac{\text{ Mass of }Zn(ClO_3)_2}{\text{ Molar mass of }Zn(ClO_3)_2}=\frac{150g}{232.29g/mole}=\frac{150}{232.29}mole

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

Zn(ClO_3)_2\rightarrow ZnCl_2+3O_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Zn(ClO_3)_2 react to give 3 mole of O_2

So, \frac{150}{232.29} moles of Zn(ClO_3)_2 react to give \frac{150}{232.29}\times \frac{3}{1} moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(\frac{150}{232.29}\times \frac{3}{1})mole\times (31.998g/mole)=\frac{150\times 3\times 31.998}{232.29\times 1}g

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

6 0
3 years ago
Read 2 more answers
Use the following information to determine the empirical formula if a compound is found to have 18.7% Li, 16.3% C, and 65.5% O A
Elina [12.6K]

Answer:

The empirical formula is Li2CO3

Explanation:

Step 1: Data given

Suppose the mass of the compound = 100 grams

The compound contains :

18.7% Li = 18.7 grams of Li

16.3 % C = 16.3 grams of C

65.0% O = 65.0 grams of O

Total = 100%

Molar mass of Li = 6.94 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate moles

Moles = Mass / molar mass

Moles Li = 18.7 grams / 6.94 g/mol = 2.65 moles

Moles C = 16.3 grams / 12.01 = 1.36 moles

Moles O = 65.0 grams / 16.0 g/mol = 4.06 moles

Step 3: Calculate the mol ratio

We divide by the smallest number of moles

Li: 2.65/1.36 ≈ 2

C: 1.36/1.36 = 1

O: 4.06/1.36 ≈ 3

The empirical formula is Li2CO3

3 0
4 years ago
Which type of environmental scientist is likely to study how different species of birds interact?
Reptile [31]
Answer: D. Ecologist

Explanation: an ecologist is someone who studies the interactions of different organisms. An ecologist would be a type of scientist who would most likely study the interactions of birds
3 0
3 years ago
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WITCHER [35]

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4 0
3 years ago
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