Answer:
Pb(NO3)2+ 2Kl →PbI2 + 2KNO3
Mg + 2HCl → MgCl2 + H2
4H2O → 4H^+ + 4OH^-
2Mg + O2 → 2MgO
Explanation:
This question has to do with the balancing of chemical reaction equations. The general rule for balancing chemical reaction equation is that the number of atoms of each element on the left hand side of the reaction equation must be equal to the number of atoms of the same element on the right hand side of the reaction equation.
This principle was followed in balancing each reaction equation above. For instance, in the burning of magnesium, there are two atoms of both magnesium and oxygen on either side of the reaction equation.
6:12:6: - this simplifies to 1:2:1 (answer)
You get the simplest form by dividing each of the 3 numbers by 6.
The equilibrium constant of the reaction is 0.042.
The reaction equation is given as;
PCl5(g) ⇄ PCl3(g) + Cl2 (g)
Recall that this equation shows the decomposition of phosphorus pentachloride.
We have the following equilibrium concentrations;
[PCI5]= 0.0095 M
[PCI3] = 0.020
[CI2] = 0.020 M
The equilibrium constant, K is obtained from;
K = [PCI3] [CI2]/[PCI5]
K = [0.020]^2/[0.0095]
K = 0.042
Learn more: brainly.com/question/17960050
<span>(1) convert body mass in lb to kg
211 lb = (211 lb)*(1 kg/2.2046 lb) = 95.71 kg
(2) calculate the amount of caffeine required for a person of that mass at the LD50
(150 mg/kg)*(95.71 kg) = 14356 mg
(3) convert % (w/w) to % (w/v)
0.61% (w/w) = 0.61 g/100 g = (0.61 g)/((100 g)/(1.00 g/mL)) = 0.61 g/100 mL
(4) calculate the volume that contains the amount of caffeine calculated
14356 mg = 14.356 g = (14.356 g)/(0.61 g/100 mL) = 2353 mL</span>