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Lunna [17]
2 years ago
14

Calculate the mass percentage of CaCO3 in the 103g mixture of CaCO3 and Na2CO3, which produces 24 litres of CO2 at one atmospher

e and 26.85 Celsius with excess of HCl​
Chemistry
1 answer:
vaieri [72.5K]2 years ago
7 0

Answer:

50%

Explanation:

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Which of the following is an example of a chemical change?
alexdok [17]

Answer:

Dissolving sugar in water, burning paper, and melting gold are all chemical changes

Explanation:

The action cannot be reversed, or undone. Therefore it is a chemical change.

Boiling water is a physical change.

3 0
2 years ago
Calculate the number of grams of oxygen gas in a 24L container at STP
romanna [79]

There are 34 g of oxygen in the container.

We can use the<em> Ideal Gas Law</em> to solve this problem.

pV = nRT

But n = \frac{m}{M}, so

pV = \frac{m}{M}RT and

m = \frac{pVM}{RT}\\

STP is 0 °C and 1 bar, so

m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\

7 0
3 years ago
Can a molecule with nonpolar bonds ever be polar? Why<br> why not?
Tanya [424]

Answer:

A molecule that has only nonpolar bonds and no polar bonds cannot be polar.

Explanation:

However, a molecule that CONTAINS nonpolar bonds is different, because it can contain polar bonds. A molecule that contains nonpolar bonds can be polar as long as it also contains polar bonds.

Pls, choose me as brainliest!

5 0
2 years ago
NH3 +<br>H2SO4 → __(NH4)2SO4​
Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

8 0
3 years ago
A 250-mL aqueous solution contains 1.56 10–5 g of methanol and has a density of 1.03 g/mL. What is the concentration in ppm?
Hoochie [10]
First, calculate for the mass of the aqueous solution by multiplying the given volume (in mL) by the density (in g/mL). In mathematical equation, that is,

        m = ρV

where m is mass, ρ is density, and V is volume. Substituting the known values,

      m = (1.03 g/mL)(250 mL) = 257.5 g

To get the concentration in ppm, divide the given mass of methanol by the mass of the solution. Note that the parts-per million (ppm) is equal to mass of solute in milligram(mg) divided by the mass of solution in kilogram (kg)

      C (in ppm) = (1.56 x 10^-6 g)(1000 mg/1 g)   / (257.5 g)(1 kg/1000 g)

Simplifying,
     C (in ppm) = (1.56 x 10^-3 mg)/ 0.2575 kg

     C (in ppm) = 0.00606 ppm

<em>Answer: 0.00606 ppm</em>
     
7 0
2 years ago
Read 2 more answers
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