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Lunna [17]
3 years ago
14

Calculate the mass percentage of CaCO3 in the 103g mixture of CaCO3 and Na2CO3, which produces 24 litres of CO2 at one atmospher

e and 26.85 Celsius with excess of HCl​
Chemistry
1 answer:
vaieri [72.5K]3 years ago
7 0

Answer:

50%

Explanation:

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The following chemical reaction occurs in a basic solution.
Dafna1 [17]

Answer:

6 moles of electrons

Explanation:

Let us consider the species NO3− and ClO−. The NO3− is oxidized to NO the oxidation number of nitrogen is decreased from +5 to +2.

The oxidation number of chlorine is increased from +1 to +3. This implies that six electrons were transferred in the balanced reaction equation shown in the question. Hence the answer.

3 0
3 years ago
Historically the troubadour was a ____.
eimsori [14]

Composer and performer of Old Occitan lyric poetryduring the High Middle Ages (1100–1350). Since the word troubadour is etymologically masculine, a female troubadour is usually called a trobairitz.


6 0
3 years ago
Does the tempurture of the vinegar affect the volcano flow
aleksandr82 [10.1K]
The temperature of vinegar does increase the rate of reaction according to the collision theory.

Hope this answers your question!


6 0
2 years ago
2. A solvent used in cleaning is found to contain only the elements carbon, hydrogen, and chlorine. When a
KIM [24]

mass of C = 0.238 g

mass of H =0.00989 g

mass of Cl = 1.05 g

Explanation:

Determine the masses of carbon, hydrogen, and chlorine in the original sample of the solvent.

First we need to calculate the molar mass of carbon dioxide (CO₂) and water (H₂O)

molar mass of CO₂ = molar mass of C × 1 + molar mass of O × 2

molar mass of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

molar mass of H₂O = molar mass of H × 2 + molar mass of O × 1

molar mass of H₂O = 1 × 2 + 16 × 1 = 18 g/mole

Now, to find the mass of carbon and hydrogen in the original sample of solvent, we devise the following reasoning:

if              44 g of CO₂ contains 12 g of C

then   0.872 g of CO₂ contains X g of C

X = (0.872 × 12) / 44 = 0.238 g of C

if               18 g of H₂O contains 2 g of H

then   0.089 g of H₂O contains Y g of H

Y = (0.089 × 2) / 18 = 0.00989 g of H

And now, we can find the mass of chlorine:

mass of sample = mass of C + mass of H + mass of Cl

mass of Cl = mass of sample - mass of C - mass of H

mass of Cl = 1.30 - 0.238 - 0.00989

mass of Cl = 1.05 g

Learn more about:

combustion reaction

brainly.com/question/14125538

#learnwithBrainly

4 0
3 years ago
A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4(aq) +2Na
slega [8]
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l

n(NaOH)=v(NaOH)*c(NaOH)

n(H₂SO₄)=0.5n(NaOH)

c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)

c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l

The concentration of the H₂SO₄ is 0.418M.

4 0
3 years ago
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