Answer : The volume of
required to neutralize is, 340 mL
Explanation :
To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of
required to neutralize is, 340 mL
<span>Chemical bonds are broken down in the reactants while a reaction is occurring. Products are the new chemical bonds that are formed.</span>