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wolverine [178]
3 years ago
12

What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?

Chemistry
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

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Answer:

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Explanation:

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Taking inverse log to both sides of the equation

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