The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to 
.
Response:
- The ratio of the period to is always approximately<u> 2·π : 1</u>
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<h3>How is the value of the ratio of the period to
calculated?</h3>
Given:
The relationship between the period, <em>T</em>, the spring constant <em>k</em>, and the
mass attached to the spring <em>m</em> is presented as follows;
Therefore, the fraction of of the period to , is given as follows;
2·π ≈ 6.23
Therefore;
Which gives;
- The ratio of the period to is always approximately<u> 2·π : 1</u>
Learn more about the oscillations in spring here:
brainly.com/question/14510622
Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;
where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
Answer:
4.6s
Explanation:
v=u+at
0=22.5+(-9.8)t
-22.5=-9.8t
t=-22.5/-9.8
t=2.295 s
The total time will double
2.295×2=4.59s
=4.6s
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