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andrew-mc [135]
3 years ago
11

PLEASE SEE MY QUESTIONS UNDER MY PROFILE AND ANSWER THEM, I REALLY NEED HELP THANK YOU!

Physics
2 answers:
Pachacha [2.7K]3 years ago
7 0

Answer:

K?              

Explanation:

     

ad-work [718]3 years ago
7 0

Answer:

ok

Explanation:

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The drawing shows two frictionless inclines that begin at ground level (h = 0 m) and slope upward at the same angle θ. One track
Elena L [17]

Answer:

a). H=2.45m

b). H_{max}=1.94m

Explanation:

For the block that stays on the track, its maximal height is attained when all of the kinetic energy  is converted to potential energy

a).

The height for the block on the longer track can by find using this equation:

\frac{1}{2}*m*v_o^2=m*g*H

Cancel the mass as a factor in each element in the equation

H=\frac{v_o^2}{2*g}

H=\frac{(6.94m/s)^2}{2*9.8m/s^2}

H=2.45m

b).

The other lost some kinetic energy so, use a projectile motion to determine the total height for the other bock:

E_k=E_p

E_k=m*g*H_1

E_k=\frac{1}{2}*m*v_o^2-\frac{1}{2}*m*v^2

m*g*H_1=\frac{1}{2}*m*(v_o^2-v^2)

Solve to v'

v^2=v_o^2-2*g*H_1

v=\sqrt{v_o^2-2*g*H_1}=\sqrt{(6.94m/s)^2-2*9.8m/s^2*1.25m}

v=4.8m/s

H_{max}=H_1+\frac{v^2*sin(50)}{2*g}=1.25m+\frac{(4.8m/s)^2*sin(50)}{2*9.8m/s^2}

H_{max}=1.94m

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3 years ago
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What is the main difference between the gas water vapor and the liquid water?
Vinil7 [7]
Water vapour has more kinetic energy.

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An object is held at an unknown height above Earth’s surface, where the acceleration due to gravity of the object is considered
Aleks04 [339]

Answer:

Options A and B.

Explanation:

Gravitational acceleration, initial height, intial speed and time are required to determine final speed. The option D is incorrect, since speed varies in time. Option C is dimentionally wrong.

The correct strategy is calculating the initial height from option B. Later, substituting time in equation A to derive an expression of the final velocity in terms of position. Hence, the required equations are options A and B.

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