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2 years ago

11

The body is subjected to a force of 0,4 N m with a shoulder of 5 cm. What is the magnitude of this force?

1 answer:

igor_vitrenko [27]2 years ago

5 0

Answer:

8N

Explanation:

the body is subjected to pressure equals to force force inverse to the area of that body given that it is in motion

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The addition of electron shells results in _____

vodka [1.7K]

Answer:

shielding of electrons

Explanation:

The addition of electrons shells results in the shielding of electrons away from the nucleus, most importantly the nuclear pull resulting from the charge.

The nucleus pulls electrons to itself due to the net positive charge on it.
As more electronic shell is added, the effect of the pull weakens outward.
The inner shell experiences the nuclear pull more than the outer shell electrons.

The effect is responsible for a wide range of properties of elements.

6 0

3 years ago

A car changes its velocity from 40.0 m/s to -5.0 m/s in 5.0 seconds what was the car average acceleration

ValentinkaMS [17]

Answ40x-50 =2334

Explanation:

idk

4 0

3 years ago

Two ropes are attached to a 35 kg object. The first rope applies a force of 20 N and the second applies a force of 55 N. If the

Goshia [24]

Answer:

$a=1.672\ m.s^{-2}$

Explanation:

Given:

mass of the object, $m=35\ kg$

forces by two mutually perpendicular ropes of the attached to the object:

$F_x=20\ N$

$F_y=55\ N$

<u>Now we find the resultant force effect due to the two given forces:</u>

$F=\sqrt{F_x^2+F_y^2}$

$F=\sqrt{(20)^2+(55)^2}$

$F=58.52\ N$

<u>Now the acceleration will be due to this resultant force:</u>

$a=\frac{F}{m}$

$a=\frac{58.52}{35}$

$a=1.672\ m.s^{-2}$

3 0

3 years ago

Read 2 more answers

3. A bottle of vitamin C contains 100 tablets and weighs 80 g. If the

Elan Coil [88]

Answer:

a

0.57g

b

20.52

c

28.5

Explanation:

a

The bottle weighs 80g with tablets

If the bottle alone weighs 23g, the tablets weigh 57g

100 tablets weigh 57g, 1 tablet weighs 0.57g

b

0.57g is one tablet, so to achieve 36 tablets we must multiply by 36

0.57 multiplied by 36 is 20.52

c

To find 50 tablets we can use the same method we used before or a slightly faster method

100 tablets is 57g, so all we have to do is halve to find 50

57 divided by 2 is 28.5

4 0

2 years ago

There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co

mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

$q_1=q_2=2.06\mu C=2.06\times 10^{-6} C$

$q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C$

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force, $F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2$

$F_1=F_3=F$

$F_{net}=\sqrt{F^2+F^2+0}-F_2$

$F_{net}=\sqrt 2F-F_2$

$F=\frac{kq^2}{d^2}$

$F_2=\frac{Kq^2}{2d^2}$

$F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})$

Where $k=9\times 10^9$

$F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})$

$F_{net}=0.208 N$

3 0

3 years ago