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AysviL [449]
3 years ago
15

The length of rectangle is represented by 8x - 3. The width of the rectangle is represented by 2x. The perimeter is 34 inches. W

hich equations represent the perimeter? Choose all of the correct answers.
Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

Answer: 20x-6 = 34

Step-by-step explanation:

Given: The length of rectangle is represented by 8x - 3.

The width of the rectangle is represented by 2x.

The perimeter is 34 inches.

Perimeter of rectangle = 2 (length + width)

Perimeter of rectangle = 2 (8x-3+2x)

Perimeter of rectangle = 2 (10x-3)

Perimeter of rectangle = 20x-6

Thus , the required equation that represent the perimeter: 20x-6 = 34

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It would be the last answer because if you multiply the percentage 30% times 70 you get 21, and 50% gets you 35.

If both dealers sold 70 total cars, Car Dealer B sold 14 more blue cars.

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Step-by-step explanation:

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3 years ago
Find the value of x and the value of y. 60 30 6
allochka39001 [22]

Answer:

  • The longest side, which is the opposite side of a right angle is the hypotenuse ( h ).

  • The opposite is the side opposite the angle involved and it is called the Perpendicular ( p ) .

  • The adjacent is the side next to the angle involved ( but not the hypotenuse ) and it is called the base ( b )

\large{ \tt{❃ \: TAKING  \: \angle \: \: A \: AS \: A \: ANGLE \: OF \: REFERENCE :  }}

  • Here , Perpendicular ( p ) = 6 , hypotenuse = y and now we're going to find the value of y first : We know :

\large{ \tt{❁ \: sin \:  60 \degree =  \frac{perpendicular}{hypotenuse} }}

\large{ \tt{➝ \:  \frac{ \sqrt{3} }{2} =  \frac{6}{y}  }}

\large{ \tt{➝ \sqrt{3}y = 6 \times 2 }}

\large{ \tt{➝ \:  \sqrt{3} \: y = 12 }}

\large{ \tt{➝ \: y=  \frac{12}{ \sqrt{ 3} } }}

\boxed{ \large{ \tt{➝ y = \: 4 \sqrt{3} }}}

\large{ \tt{❇ \: TAKING  \: \angle \: B \: AS \: THE \: ANGLE \: OF \: REFERENCE}} :

  • Here - Perpendicular ( p ) = x , hypotenuse = y = 4 √ 3 and Now , we're gonna find the value of x :

\large{ \tt{❊ \: sin  \: 30 \degree =  \frac{perpendicular}{hypotenuse} }}

\large{ \tt{⟶ \:  \frac{1}{2} =  \frac{x}{4 \sqrt{3} }  }}

\large{ \tt{⟶ \: 2x = 4 \sqrt{3} }}

\large{ \tt{⟶ \: x =  \frac{4 \sqrt{3} }{2} }}

\boxed{\large{ \tt{⟶ \: x = 2 \sqrt{3} }}}

\boxed{  \large{ \tt{❈ \:  OUR \: FINAL \: ANSWER :  \boxed{ \tt \: x = 2 \sqrt{3}   \: \: y = 4 \sqrt{3} }✓}}}

  • And we're done! Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help ! :)

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

3 0
3 years ago
Solve for x: 3|x − 3| 2 = 14
bixtya [17]
Go to a website called Mathpapa. It is an algebra calculator and it solves it for you
3 0
4 years ago
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