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3 years ago

11

13. Nathan completed 60% of the passes he attempted during the last football season. If he attempted 90 passes, how many did he

complete?

1 answer:

shutvik [7]3 years ago

5 0

Answer:

54 passes

Step-by-step explanation:

90 x 0.6 = 54

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What is the difference between the integers -11 and -3

Svetach [21]

-11 - -3 = -8 hope that helps!!

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3 years ago

Read 2 more answers

Given that ABCD is a rectangle, find the perimeter of the figure below. Round your answer to the nearest tenth. *

BARSIC [14]

Answer:

<em><u>ANSWER</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>OPTION</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em>

<em><u>19.7FT</u></em>

PERIMETER OF FIG.=2 (L+B)-B + PI*R

=2 (6+3)-3 + 3.14*1.5

=18-3+4.71

=15+4.71

=19.71

=19.7 ft

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3 years ago

Rich deposited money into a bank account that earned 2.5% simple interest each year. After 2 years, he had earned $14.65 in inte

adelina 88 [10]

Rich deposited $293 for 2 years at 2.5% simple interest rate

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4 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

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3 years ago

Your town has seen a steady decrease of job opportunities by the amount of 10% every year. If the number of jobs available at th

anzhelika [568]

350,000*-10%=?
350,000*90%=?
?=315000

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3 years ago