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mixas84 [53]
2 years ago
10

I need help now it’s an iready

Mathematics
2 answers:
Oksana_A [137]2 years ago
6 0

Answer:

12h+135?

Step-by-step explanation: add the like terms together I assume.

IrinaVladis [17]2 years ago
5 0

Answer:

12h+135

Step-by-step explanation:

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The function f(x) varies directly with x and f(x)=12 when x=8
malfutka [58]
F(x) = kx
12 = 8k
k = 12/8 = 3/2

Required equation is f(x) = 3/2 x
4 0
3 years ago
Which pair of ratios forms a proportion?​
bogdanovich [222]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What's the next number 2 7 8 3 12 9
puteri [66]

The <em>correct answer</em> is:

4.

Explanation:

Taking these numbers as groups of three, we have 2, 7, 8; 3, 12, 9.

In the first group, we can see that we first add 5 and then add 1.

The next group seems to start from the next consecutive number. That is, the first group starts with 2, and the next group starts with 3. The next terms in the second group are found by adding 5 to the second term of the first group (12 = 7+5) and then adding 1 to the third term of the first group (9=8+1); this is because we added 5 and added 1 previously.

Following this pattern, the next group of three would start from the next consecutive number up, 4. The next two terms would be 17 (12+5=17) and 10 (9+1=10).

7 0
3 years ago
Read 2 more answers
Simplify <br> 1+sinx/cosx+cosx/1+sinx
Dmitry [639]
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}
\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}
\frac{2}{cos(x)}
2sec(x)
6 0
2 years ago
Explain step by step please thank you!
ddd [48]

Answer:

Number of students in district = 3,055 students

Step-by-step explanation:

Given:

Ratio [Teachers to students] = 2 : 47

Total number of teachers in district = 130

Find:

Number of students in district

Computation:

Number of students in district = Total number of teachers in district[47/2]

Number of students in district = 130[47/2]

Number of students in district = 65[47]

Number of students in district = 3,055 students

5 0
3 years ago
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